Answer:
The intensity will be 1/9 as much.
Explanation:
The intensity of the light or any source is inversely related to the square of the distance.

Now according to the question the distance is increased by three times than,

Therefore,

Therefore the intensity will become 1/9 times to the initial intensity.
<span>Wind is nature's way of balancing the temperature between hot and cold. Wind always flows from heat to cool. When night falls, the air cools. And since it gets cooler at night it reverses.</span>
Answer:
The distance of the goggle from the edge is 5.30 m
Explanation:
Given:
The depth of pool (d) = 3.2 m
let 'i' be the angle of incidence
thus,
i = 
i = 67.75°
Now, Using snell's law, we have,
n₁ × sin(i) = n₂ × 2 × sin(r)
where,
r is the angle of refraction
n₁ is the refractive index of medium 1 = 1 for air
n₂ is the refractive index of medium 1 = 1.33 for water
now,
1 × sin 67.75° = 1.33 × sin(r)
or
r = 44.09°
Now,
the distance of googles = 2.2 + d×tan(r) = 2.2 + (3.2 × tan(44.09°) = 5.30 m
Hence, <u>the distance of the goggle from the edge is 5.30 m</u>
Answer:
1524 nm.
Explanation:
Angular separation of n th minima is given by the expression
Sin θ = n λ / a
Where λ is wavelength of light used and a is separation between two slits .
a = n λ / sin θ
For a to be minimum, sinθ has to be maximum .
maximum value of sin of any angle is 1 .
so the relation becomes as follows
a = n λ
n = 2 , λ = 762 nm.
a = 2 x 762 nm
= 1524 nm.