Intensity:
Decibels
Amplitude:
Meters
Frequency: Hertz
<u>Explanation:</u>
The Wave is not visible to eyes and they can easily propagate through vacuum. the average power travelling at a given period of time in a space is the intensity. Decibels is the measure of intensity. it is measured in the decibel scale. The wave's strength and the intensity gives the amplitude of wave. It is measured using meters.
The wave's amplitude and the energy has a direct proportionality. The number occurrence of wave cycles per second refers to the frequency of wave. it is measured in hertz. it is also measured as the number of cycles that occurs per second.
Answer:
The direction of the resulting force on this current is due east.
Explanation:
Given;
direction of the magnetic field to be due north
Applying right hand rule which states that: to determine the direction of the magnetic force on a positive moving charge point the thumb of the right hand in the direction of velocity v, the fingers in the direction of magnetic field B, and a perpendicular to the palm points in the direction of magnetic force.
Since the magnetic force must be perpendicular to the magnetic field, and direction of the magnetic field is due north, then the magnetic force must be due East.
Therefore, the direction of the resulting force on this current is due east.
Answer:
(a) 490 N on earth
(b) 80 N on earth
(c) 45.4545 kg on earth
(d) 270.27 kg on moon
Explanation:
We have given 1 kg = 9.8 N = 2.2 lbs on earth
And 1 kg = 1.6 N = 0.37 lbs on moon
(a) We have given mass of the person m = 50 kg
As it is given that 1 kg = 9.8 N
So 50 kg = 50×9.8 =490 N
(b) Mass of the person on moon = 50 kg
As it is given that on moon 1 kg = 1.6 N
So 50 kg = 50×1.6 = 80 N
(c) We have given that weight of the person on the earth = 100 lbs
As it is given that 1 kg = 2.2 lbs on earth
So 100 lbs = 45.4545 kg
(d) We have given weight of the person on moon = 100 lbs
As it is given that 1 kg = 0.37 lbs
So 100 lbs ![\frac{100}{0.37}=270.27kg](https://tex.z-dn.net/?f=%5Cfrac%7B100%7D%7B0.37%7D%3D270.27kg)
The answer will be 8 because kedks
Answer:
The maximum torque in the coil is
.
Explanation:
Given that,
Number of turns in the circular coil, N = 50
Radius of coil, r = 5 cm
Magnetic field, B = 0.5 T
Current in coil, I = 25 mA
We need to find the magnitude of the maximum possible torque exerted on the coil. The magnetic torque is given by :
![\tau=NIAB\ \sin\theta](https://tex.z-dn.net/?f=%5Ctau%3DNIAB%5C%20%5Csin%5Ctheta)
For maximum torque, ![\theta=90^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D90%5E%7B%5Ccirc%7D)
![\tau=NIAB\\\\\tau=50\times 25\times 10^{-3}\times \pi (0.05)^2\times 0.5\\\\\tau=4.9\times 10^{-3}\ N-m](https://tex.z-dn.net/?f=%5Ctau%3DNIAB%5C%5C%5C%5C%5Ctau%3D50%5Ctimes%2025%5Ctimes%2010%5E%7B-3%7D%5Ctimes%20%5Cpi%20%280.05%29%5E2%5Ctimes%200.5%5C%5C%5C%5C%5Ctau%3D4.9%5Ctimes%2010%5E%7B-3%7D%5C%20N-m)
So, the maximum torque in the coil is
.