4 years ago

Why do toasters always have a setting that burns the toast to a horrible crisp, which no decent human being would eat?

2 answers:

Taya2010 [7]4 years ago

6 0

Some people love burnt toast. I personally do not, but I know many people who do. Typically that setting is for stuff that takes longer to get crispy.

padilas [110]4 years ago

4 0

My wife makes toast and hot dogs in the toaster oven. She likes them both burned to a horrible crisp. Sometimes she'll run either of them again, for a second cycle. I am not making this up.

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The Large Hadron collider (LHC) is a huge piece of equipment designed and built in order to make new scientific discoveries. The

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Answer:

Explanation:

"The Large Hadron collider (LHC) is a <em>huge piece of equipment designed and built in order to make new scientific discoveries.</em>"

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3 years ago

You want the current amplitude through a inductor with an inductance of 4.70 mH (part of the circuitry for a radio receiver) to

goldenfox [79]

Answer:

f = 1.69*10^5 Hz

Explanation:

In order to calculate the frequency of the sinusoidal voltage, you use the following formula:

$V_L=\omega iL=2\pi f i L$ (1)

V_L: voltage = 12.0V

i: current = 2.40mA = 2.40*10^-3 A

L: inductance = 4.70mH = 4.70*10^-3 H

f: frequency = ?

you solve the equation (1) for f and replace the values of the other parameters:

$f=\frac{V_L}{2\pi iL}=\frac{12.0V}{2\pi (2.4*10^{-3}A)(4.70*10^{-3}H)}=1.69*10^5Hz$

The frequency of the sinusoidal voltage is f

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3 years ago

While running around the track at school, Milt notices that he runs due East in the 100m homestretch and due West on the 100m ba

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They have equal magnitudes and opposite directions.

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3 years ago

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a 4kg metal block absorbs 5000j of energy and increases to a temperature of 22°c. the metal has a specific heat capacity of 250j

e-lub [12.9K]

Answer:

17 °C

Explanation:

From specific Heat capacity.

Q = cm(t₂-t₁)................. Equation 1

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make t₁ the subject of the equation

t₁ = t₂-(Q/cm)............... Equation 2

Given: t₂ = 22 °C, Q = 5000 J, m = 4 kg, c = 250 J/kg.°c

Substitute into equation 2

t₁ = 22-[5000/(4×250)

t₁ = 22-(5000/1000)

t₁ = 22-5

t₁ = 17 °C

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3 years ago