I’m going to assume initial velocity is 0.
Use Newton’s second law:
F = m•a
F/m = a
14.0/32.5kg= 28/65 m/s^2
Use constant SUVAT acceleration formulae:
S- displacement - what we need to find out
U - initial velocity - 0
V
A - 28/65 m/s^2
T - 10 seconds
S = ut + 1/2at^2
Since u = 0
S = 1/2at^2
1/2• 28/65 • 10^2 = 21.5metres~
Answer is 21.5 metres
~Hoodini, here to help.
Answer:
The speed is 13 m/s
Explanation:
In this problem, we have two reference frames:
- The reference frame of the observer on the ground, O
- The reference frame of the observes on the train, O', moving with velocity with respect to O (here we have taken north as positive direction, so since the train is moving south, we wrote it as a negative number)
For the observer on the ground, O, Sydney is moving with velocity
(positive because it's moving north)
So, we can find Sydney's velocity with respect to the frame O' as follows
So, the camera crew on the train observe Sydney moving at 13 m/s north
The equation is unbalanced because the number of hydrogen atoms and sodium atoms is not equal in the reactants and the products
Answer:
Explanation:
Given
ambient Pressure =98.10 kPa
(a)gauge pressure 152 kPa
we know
Absolute pressure=gauge pressure+Vacuum Pressure
=152+98.10=250.1 kPa or 36.27 psi
(b)=67.5 Torr or 8.99 kpa
as 1 Torr is 0.133 kPa
=8.99+98.10=107.09 kPa or 15.53 psi
(c)=0.1 bar or 10 kPa
Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi
as 1 kPa is equal to 0.145 psi
(d)=0.84 atm or 85.113 kPa
as 1 atm is equal to 101.325 kPa
=98.10-85.11=12.99 kPa or 1.88 psi
Answer:
The tension in the rope is 262.88 N
Explanation:
Given:
Weight N
Length of rope m
Initial speed of ball
For finding the tension in the rope,
First find the mass of rod,
( )
kg
Tension in the rope is,
N
Therefore, the tension in the rope is 262.88 N