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ELEN [110]
4 years ago
5

Write an application that displays a series of at least five student ID numbers (that you have stored in an array) and asks the

user to enter a numeric test score for the student. Create a ScoreException class, and throw a ScoreException for the class if the user does not enter a valid score (less than or equal to 100). Catch the ScoreException, display the message Score over 100, and then store a 0 for the student’s score. At the end of the application, display all the student IDs and scores. g
Computers and Technology
1 answer:
babymother [125]4 years ago
8 0

Answer:

See explaination for the program code

Explanation:

// ScoreException.java

class ScoreException extends Exception

{

ScoreException(String msg)

{

super(msg);

}

}

// TestScore.java

import java.util.Scanner;

public class TestScore

{

public static void main(String args[]) throws ScoreException

{

Scanner sc = new Scanner(System.in);

int studentId[] = { 1201, 1202, 1203, 1204, 1205 };

int scores[] = new int[5];

int score = 0;

for(int i = 0; i < studentId.length; i++)

{

try

{

System.out.print("Enter a numeric test score for the student"+(i+1)+" of Id "+studentId[i]+" : ");

score = sc.nextInt();

if(score < 0 || score > 100)

{

scores[i] = 0;

throw new ScoreException("Input should be between 1 and 100");

}

else

{

scores[i] = score;

}

}

catch(ScoreException ex)

{

System.out.println("\n"+ex.getMessage()+"\n");

}

}

//displaying student details

System.out.println("\n\nStudent Id \t Score ");

System.out.println("=============================");

for(int i = 0; i < studentId.length; i++)

{

System.out.println(studentId[i]+"\t\t"+scores[i]);

}

}

}

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Modify the list according to the following: append the smallest value at the end of the list when all numbers in the list are ne
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Answer:

The solution code is written in Python 3:

  1. def modifyList(listNumber):
  2.    posCount = 0
  3.    negCount = 0
  4.    for x in listNumber:
  5.        if x > 0:
  6.            posCount += 1
  7.        else:
  8.            negCount += 1
  9.    
  10.    if(posCount == len(listNumber)):
  11.        listNumber.append(max(listNumber))
  12.    
  13.    if(negCount == len(listNumber)):
  14.        listNumber.append(min(listNumber))
  15.    
  16.    print(listNumber)
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  18. modifyList([1,99,8])
  19. modifyList([-1,99,-81])

Explanation:

The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).

To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).

If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).

If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.

At last we can print the listNumber (Line 17).

If we test our function using the three sets of input list, we shall get the following results:

[-1, -99, -81, -99]

[1, 99, 8, 99]

[-1, 99, -81]

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