2 years ago

Write -4i + (1/4-5i)-(-3/4+8i)+17i as a complex number in standard form

Mathematics

1 answer:

Alex17521 [72]2 years ago

5 0

Answer:

Step-by-step explanation:

$-4i+\left(\dfrac{1}{4}-5i\right)-\left(-\dfrac{3}{4}+8i\right)+17i\\\\=-4i+\dfrac{1}{4}-5i+\dfrac{3}{4}-8i+17i\\\\=\left(\dfrac{1}{4}+\dfrac{3}{4}\right)+(-4i-5i-8i+17i)\\\\=\dfrac{1+3}{4}+(-4-5-8+17)i\\\\=\dfrac{4}{4}+0i\\\\=1$

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Write -4i + (1/4-5i)-(-3/4+8i)+17i as a complex number in standard form​

Write -4i + (1/4-5i)-(-3/4+8i)+17i as a complex number in standard form