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Tpy6a [65]
3 years ago
7

NOT A TEST AND I WILL GIVE BRAINLEIST DON'T ANSWER IF YOU DON'T KNOW

Chemistry
1 answer:
barxatty [35]3 years ago
5 0

Answer:

In the nucleus of an atom ,there are protons & neutrons. Protons have charge of 1.6× 10^-19 C, while neutrons have 0C charges. Electrons orbit outside the atom. Their charge is - 1.6 ×10^-19C

Explanation:

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Based on this reaction, find how many moles of co can be obtained starting with 7 mol ch4?
Klio2033 [76]
I will solve the question assuming the reaction used as below
1 CH4(g) + 1 H2O(g) ==> 1 CO(g) + 3 H<span>2(g)

In the reaction, CH4 is the reactant and CO is the wanted product. If you look at the coefficient of the substance, for every 1 mol of CH4 react there will be 1 mol of CO produced. So, if you have 7 moles of CH4 the amount of CO produced would be: 7 moles * 1/1= 7 moles of CO</span>
5 0
4 years ago
Read 2 more answers
What is the [oh−] of a solution if its ph = 8.78? answer in units of m?
dexar [7]
PH = -log([H+])
[H+] = 10^(-pH)

[H+] = 10^(-8.78) = 1.65*10^-9

[H+][OH-] = Kw
Kw = 1.0*10^-14 at 25 degrees celsius.

[OH-] = Kw/[H+] = (1.0*10^-14)/(1.65*10^-9) = 6.06*10^-6

The concentration of OH- ions is 6.1*10^-6 M.
7 0
4 years ago
Given the propane molecule C3H8(g)! a) What is the balanced equation for the combustion of propane in O2?(20 pts.) b) What is th
lubasha [3.4K]

Answer:

The answer to your question is below

Explanation:

Propane = C₃H₈

Process

1.- Write the chemical reaction

                     C₃H₈  +  O₂   ⇒   CO₂  +  H₂O

balanced chemical reaction

                      C₃H₈  +  5O₂   ⇒  3CO₂  +  4H₂O

               Reactants      Elements     Products

                      3                    C                  3

                      8                    H                  8

                     10                    O                 10

b) Standard enthalpy

Propane                  -104.7 kJ/mol

Oxygen                         0   kJ/mol

Carbon dioxide      -393.5 kJ/mol

Water                      -241.8 kJ/mol

ΔH° = ∑ΔH° products - ∑H° reactants

ΔH° = 3(-393.5) + 4(-241.8) - [(-104.7) + 0]

-Simplification

ΔH° = -1180.5 kJ/mol - 967.2 kJ/mol + 104.7 kJ/mol

ΔH° = - 2042.5 kJ/mol

This reaction is exothermic because ΔH° is negative.

4 0
3 years ago
Definition in your own words
Galina-37 [17]

Answer:

Liquid,gas,solid and plasma

Explanation:

There four phases of matter. These phases are the gas phase(steam), the liquid phase(water), the solid phase(Ice) and finally the plasma phase(moucous).

4 0
3 years ago
HBrO(aq) + H2O(l) ⇄ H3O+(aq) + BrO−(aq)   Keq=2.8×10−9
Verdich [7]

Answer: The equilibrium concentration of BrO^- will be much smaller than the equilibrium concentration of HBrO, because Keq<<1

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

HBrO(aq)+H_2O(l)\rightarrow H_3O^+(aq)+BrO^-(aq)

The expression for K_{eq} is written as:

K=\frac{[H_3O^+]\times [BrO^-]}{[HBrO]}

Concentration of pure solids and liquids is taken as 1.

K=2.8\times 10^{-9}

Thus as K_{eq} , That means the concentration of products is less as the reaction does not proceed much towards the forward direction.

7 0
3 years ago
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