Answer:
the speed of the electron at the given position is 106.2 m/s
Explanation:
Given;
initial position of the electron, r = 9 cm = 0.09 m
final position of the electron, r₂ = 3 cm = 0.03 m
let the speed of the electron at the given position = v
The initial potential energy of the electron is calculated as;
When the electron is 3 cm from the proton, the final potential energy of the electron is calculated as;
Apply the principle of conservation of energy;
ΔK.E = ΔU
Therefore, the speed of the electron at the given position is 106.2 m/s
Answer
Explanation:
Convert the time to seconds = 0.6 × 60 × 60
= 2160seconds
Velocity = distance ÷ time
Velocity = 500 ÷ 2160
Velocity = 0.23meters per seconds(m/s)
Acceleration = Velocity ÷ time
Acceleration = 0.23 ÷ 2160
Acceleration = 0.000106meters per seconds ²(m/s²)
Resultant: in biomechanics, often resultant vectors are calculated, in which case a single vector is formed by combining (or summing) two or more other vectors. For example, combining horizontal and vertical forces into a resultant force.
Proton I think if I remember right
Answer:
I1 < I2
V1 > V2
Explanation:
Let the EMF of both the batteries is E and the internal resistance of both the cells is r.
The relation between the current and the EMF is given by
where, R be the resistance connected in the circuit.
the relation between the terminal potential difference and the EMF is given by
V = E - Ir
where, V is the terminal potential difference
If R1 is connected,
The current is given by
.... (1)
The terminal potential difference is given by
..... (2)
If R2 is connected,
The current is given by
.... (3)
The terminal potential difference is given by
..... (4)
As given in the question, R2 > R1
So, by the equation (1) and (3), we get
I1 < I2
and by the equation (2) and (4) ,we get
V1 > V2