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2 years ago

Please help me with this i need your help

Physics

1 answer:

krek1111 [17]2 years ago

3 0

Answer:
Speed of the wave is 7.87 m/s.
Explanation:
It is given that, tapping the surface of a pan
of water generates 17.5 waves per second
We know that the number of waves per
second is called the frequency of a wave.
So, f= 17.5 HZ
Wavelength of each wave,
A = 45 cm = 0.45 m
Speed of the wave is given by:
175 × 0.45
V= 7.87 m/s
So, the speed of the wave is 7.87 m/s
Hence, this is the required solution.

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The drawing shows an equilateral triangle, each side of which has a length of 2.00 cm. Point charges are fixed to each corner, a

Kipish [7]

Answer:

$-2.60097\times 10^{-6}\ C$

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

r = Distance between charges = 2 cm

The electric force is given by

$F=\dfrac{k4\times 10^{-6}q_A}{r^2}$

Also

$F=\dfrac{k4\times 10^{-6}q_B}{r^2}$

The sum of the force is given by

$\sum F=\dfrac{k4\times 10^{-6}q_A}{r^2}cos 30+\dfrac{k4\times 10^{-6}q_B}{r^2}cos 30\\\Rightarrow \sum F=2\dfrac{k4\times 10^{-6}q_A}{r^2}cos 30\\\Rightarrow q_a=\dfrac{\sum Fr^2}{2\times k4\times 10^{-6}cos30}\\\Rightarrow q_a=\dfrac{405\times 0.02^2}{2\times 8.99\times 10^9\times 4\times 10^{-6}cos30}\\\Rightarrow q_a=2.60097\times 10^{-6}\ C$

Thus $q_a=q_b=-2.60097\times 10^{-6}\ C$ .

The negative sign is because the force points downward which is taken as negative

7 0

4 years ago

To drive a typical car at 40 mph on a level road for onehour requires about 3.2 × 107 J ofenergy. Suppose one tried to store thi

Ainat [17]

Answer:

$\omega=943\ rad/s$

Explanation:

Given that,

Speed of the car, v = 40 mph

Energy required, $E=3.2\times 10^7 J$

Radius of the flywheel, r = 0.6 m

Mass of flywheel, m = 400 kg

The kinetic energy of the disk is given by :

$E_k=\dfrac{1}{2}I\omega^2$

I is the moment of inertia of the disk, $I=\dfrac{mr^2}{2}$

$\omega^2=\dfrac{2E_k}{I}$

$\omega^2=\dfrac{2E_k}{\dfrac{mr^2}{2}}$

$\omega^2=\dfrac{2\times 3.2\times 10^7}{\dfrac{400\times (0.6)^2}{2}}$

$\omega=942.80\ rad/s$

$\omega=943\ rad/s$

So, the angular speed of the disk is 943 rad/s. Hence, this is the required solution.

8 0

3 years ago

A small metal bead, labeled A, has a charge of 26 nC . It is touched to metal bead B, initially neutral, so that the two beads s

adell [148]

Answer:

$q_A=25.953\ \rm nC$

$q_B=0.047\ \rm nC$

Explanation:

Given:

Total initial charge on bead A=26 nC
The distance between them=5 cm
Magnitude o the force between them $=4.4\times10^{-4}$

Using coulombs law the force between two charged particle is $\dfrac{q_Aq_B}{4\pi \epsilon_0 r^2}$

where r is the radial distance between them

According to question we have

$4.4\times10^{-4}=\dfrac{q_Aq_B\times9\times10^9}{0.05^2}\\\\4.4\times10^{-4}=\dfrac{q_A(q_A-26\times10^{-9})\times9\times10^9}{0.05^2}\\q_A=25.953\ \rm nC\\q_B=0.047\ \rm nC$

Hence the charge on two metal beads is calculated.

5 0

3 years ago

The forces acting on a sailboat are 390n north and 180n east. if the boat (including crew) has a mass of 270 kg, what are the ma

patriot [66]

F=ma so a=F/m

ax=180/270=0.67m/s^2
ay=390/270=1.44m/s^2

Magnitude = sqrt((0.67^2)+(1.44^2))=1.59m/s^2

Direction- Tan(x)=0.67/1.44=0.47 Tan^-1(x)=25 degrees

4 0

3 years ago

Read 2 more answers

a diver on a board 7.5m above the water walks off the end with a horizontal velocity of 2.3 m/s when they hit the surface of the

m_a_m_a [10]

Answer:

2.846m

Explanation:

The diver is performing projectile motion.

To find x(final), we are going to use the equation x(final) = v(initial)*t + x(initial)

x(initial) = 0

x(final) = ?

v(initial) = 2.3 m/s

we don't know t

To find t we will use y(final) = 1/2*(-9.8)*t^2 + v(initial in the y dir.)*t + y(initial)

- 9.8 in the acceleration in the y dir.

y(final) = 0

y(initial) = 7.5

v(initial in the y dir.) = 0

If we solve for t we get: t = 1.237s

Now we have all the components to solve for x(final) in x(final) = v(initial)*t + x(initial)

x(final) = 2.3*1.237 + 0

x(final) = 2.846m

6 0

3 years ago