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4 years ago

7

What happens when close off the end of a garden hose?

1 answer:

Allushta [10]4 years ago

5 0

Water dosent come out

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PLEASE HELP! Compare and contrast between reflection and refraction. Be sure to be specific in your explanation and state in you

horsena [70]

Most ultrasound technicians train in an associates degree, but can also get a bachelors degree in the field. There is also certification programs you can go through. Hope this helped!!! :)

7 0

4 years ago

A proton moves through a region of space where there is a magnetic field B⃗ =(0.64i+0.40j)T and an electric field E⃗ =(3.3i−4.5j

fenix001 [56]

Answer:

$F = (8.35 \times 10^{-16})\hat i - (12.12 \times 10^{-16})\hat j +(1.35 \times 10^{-16})\hat k$

Explanation:

When a charge is moving in constant magnetic field and electric field both then the net force on moving charge is vector sum of force due to magnetic field and electric field both

so first the force on the moving charge due to electric field is given by

$\vec F_e = q\vec E$

$\vec F_e = (1.6 \times 10^{-19})(3.3 \hat i - 4.5 \hat j) \times 10^3$

$\vec F_e = (5.28 \times 10^{-16}) \hat i - (7.2 \times 10^{-16}) \hat j$

Now force on moving charge due to magnetic field is given as

$\vec F_b = q(\vec v \times \vec B)$

$\vec F_b = (1.6 \times 10^{-19})((6.6 \hat i+2.8 \hat j−4.8 \hat k) \times 10^3 \times (0.64 \hat i + 0.40 \hat j) )$

$\vec F_b = (4.22 \times 10^{-16})\hat k - (2.87 \times 10^{-16})\hat k - (4.92 \times 10^{-16})\hat j + (3.07 \times 10^{-16}) \hat i$

$\vec F_b = (3.07\times 10^{-16})\hat i - (4.92 \times 10^{-16})\hat j + (1.35 \times 10^{-16})\hat k$

Now net force due to both

$F = F_e + F_b$

$F = (8.35 \times 10^{-16})\hat i - (12.12 \times 10^{-16})\hat j +(1.35 \times 10^{-16})\hat k$

7 0

3 years ago

Consider a car turning about curved path of radius 40 m and banking angle 5 degree without skidding.

Fudgin [204]

Explanation:

speed of curved path=under root of Mew and gravity

smooth surface Mew=0

so under root of 0×g

=0

4 0

3 years ago

Cardiovascular fitness measures the health of which body system?

Aloiza [94]

Answer:

I believe it is the circulatory system.

Explanation:

Have a nice day.

5 0

3 years ago

Freight trains can produce only relatively small accelerations and decelerations. What is the final velocity, in meters per seco

Crank

Answer:

Explanation:

Initial velocity of train u = 3.4 m⁻¹ , Acceleration a = .065 ms⁻² ,

time t = 9.75 x 60 = 585 s.

v = u + at

= 3.4 + .065 x 585

= 41.425 m / s

distance travelled during the acceleration ( s )

s = ut + 1/2 at²

= 3.4 x 585 + .5 x .065 x 585²

= 1989 + 11122.31

= 13111.31 m .

again for slowing process

u = 41.425 m / s

v = u -at

0 = 41.425 - 0.625 t

t = 66.28 s

v² = u² - 2as

0 = 41.425² - 2 x .625 s

s = 1372.82 m

7 0

3 years ago