I WILL mARK U BRAINLLYIST
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Answer:
400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed
Explanation:
Let's assume concentration of brine salt solutions are in %(w/v) unit.
Final mixture has a concentration of 11.2% salt and volume of 1 L or 1000 mL
Hence, amount of salt in final mixture =
Suppose x mL of 4% salt solution and (1000-x) mL of 16% salt solution need to be mixed to get final mixture
So, amount of salt in x mL of 4% salt solution =
amount of salt in x mL of 16% salt solution =
Hence,
or,
So, 400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed