Givens
=====
Ti = 92.8 oC = 92.8 + 273 = 365.8
T2 = 0.4 oC = 0.4 + 273 = 273.4
Vi = 1.54 mL
Vf = ?????
Formula
======
Vi/Ti = Vf / Tf
1.54 / 365.8 = Vf / 273.4
Calculations
=========
1.54 * 273.4 / 355.8 = Vf
vf = 1.15 mL
Comment
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if your teacher is concerned about sig digs, the answer is 1 mL. I'm not sure how to show that it is 1 sig dig. You can ask about this.
We will assume that the CM of the arm is at "L"
from the elbow, and the ball is at 34cm. Then the net torque is computed
by:
Net τ = 1.42 N * 34 cm + 1.50 kg * 9.8m/s² * 34 cm/2 – 12.6 N*2.75cm
= 48.28 N*cm + 1.50kg * 9.8m/s² * 34 cm/2 – 12.6 N*2.75cm
= 48.28 N*cm + 499.8 – 34.65 N*cm
τ = 513.43 N*cm or
5.1343 N*m
Answer:
Explanation:
Sine the plane is horizontal , effect of gravity on horizontal motion will be nil.
Since no friction is acting on it , no horizontal force is acting on it. Since no vertical ,no horizontal force is acting on it , it will have uniform motion ,ie its velocity will remain unchanged during its motion , no matter how long the path is.
So , velocity along the path will remain unchanged.