<h2>
Answer:</h2>
8.00Ω
<h2>
Explanation:</h2>
The resistance (R) of a wire is related to the length (L) of the wire as follows;
R = ρL/ A ----------------(i)
Where;
ρ = resistivity of the wire
A = crossectional area of the wire.
Taking the resistivity and area constant, equation (i) can be re-written as;
R = k L -------------(ii)
where;
k = constant = ρ/L
<em>From equation (ii);</em>
The resistance is directly proportional to length. i.e when the resistance increases, the length will also increase and vice-versa. This can be written as follows;
= k
<em>This implies that;</em>
= -------------------(iii)
<em>Where;</em>
and are the initial values of the resistance and length respectively
and are the final values of the resistance and lenght respectively.
<em>From the question;</em>
= 4.00Ω
= 8.00m
= 16.00m
<em>Substitute these values into equation(iii) as follows;</em>
=
<em>Cross multiply;</em>
4.00 x 16.00 = x 8.00
64.00 = 8.00
<em>Solve for </em><em>;</em>
= 64.00/ 8.00
= 8.00Ω
Therefore the resistance of the wire after it has been stretched is 8.00Ω