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stellarik [79]
3 years ago
11

Which statement best compares a scientific theory and an opinion?

Physics
1 answer:
Furkat [3]3 years ago
8 0

Answer: c opinion is something ppl just suggest but a theory needs proof before it is confirmed

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If a nucleus decays by successive b, a, a emissions, its mass number will Group of answer choices decrease by seven. decrease by
nirvana33 [79]

Answer:

The mass number will decrease by eight (8).

Explanation:

Given;

successive beta (b), alpha (a), alpha (a) emissions.

Generally, when a radioactive element emits a beta-particle (b), its mass number doesn't increase but its atomic number increases by 1 . (^{0}_{-1}\beta )

Also when a radioactive element emits an alpha-particle (a), its mass number decreases by 4, while its atomic number decrease by 2. (^4_2\alpha)

For the given question, a successive beta (b), alpha (a),  and alpha (a) emissions = (0) + (-4) + (-4) = -8

Thus, when a radioactive element emit a successive beta (b), alpha (a), alpha (a) particles, the mass number will decrease by eight (8).

<u>To learn more, please visit:</u> brainly.com/question/23276969

7 0
3 years ago
The ability to react with air is what
neonofarm [45]
Reactivity is the ability to react with other substances/(the answer is reactivity)
5 0
4 years ago
Read 2 more answers
1) [25 pts] A 90-kg merry-go-round of radius 2.0 m is spinning at a constant speed of 20 revolutions per minute. A kid standing
Ray Of Light [21]

Answer:

(A) 180 kg·m²

(B) 0.111 rad/s²

(C) The number of revolutions the merry-go-round will complete until it finally stops is 3.142 or π rev

Explanation:

The equation of the moment of inertia of a solid cylinder is presented as follows;

I = \frac{1}{2}MR^2

Where:

I = Moment of inertia of the merry-go-round

M = Mass of the merry-go-round

R = Radius of the merry-go-round

Therefore, I = 1/2×90×2² = 180 kg·m²

(B) For the angular acceleration we have;

Therefore, since the force × radius = The torque, we have, angular acceleration is found as follows

F × R = τ

10.0 × 2.0 = 20 = I×α = 180×α

α = 20/180 = 0.111 rad/s².

angular acceleration = 0.111 rad/s².

(C) Here we have ω₀ = 20 rev/ min = 20×2×π rad/min = π·40/60 rad/s

2/3·π rad/s

ω = ω₀ - α×t

∴ t = ω₀/α = (2/3·π rad/s)/(0.111 rad/s²) = 18.85 s

Hence we have

θ = ω₀·t + 1/2·α·t², plugging in the values, we have;

θ = 2/3·π×18.85 - 1/2·0.111·18.85²

θ = 19.74 rad

Therefore, since 2·π radian = 1 revolution

The number of revolutions the merry-go-round will complete until it stops is 19.74/(2·π) = 3.142 or π revolutions.

5 0
4 years ago
UCaShoTLLOuuj9D4vqFtTpSQ<br><br> search
Bond [772]

Answer:

ok i searched it up in google and it showed links XDDDD

Explanation:

4 0
3 years ago
¿Qué cantidad de calor se desprende cuando 125 g de vapor de agua a 140 ºC se enfrían y congelan produciendo 125 g de hielo a -1
tensa zangetsu [6.8K]

Answer:

i dont know

Explanation:

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