Question

A flat, circular loop has 20 turns. The radius of the loop is 10.0 cm and the current through the wire is 0.50 A. Determine the magnitute of magnetic field at the center of the loop.

Answer 1

Answer:$B=6.28\times 10^{-5} T$

Explanation:

Given

No of turns $n=20 turns$

radius of Loop $r=10 cm=0.1 m$

current $i=0.5 A$

Magnetic Field at center of loop is given by

$B=\frac{\mu _0nI}{2r}$

$B=\frac{4\pi \times 10^{-7}\times 20\times 0.5}{2\times 0.1}$

$B=628.4\times 10^{-7} T$

$B=6.28\times 10^{-5} T$