Question

Astronauts land on another planet and measure the density of the atmosphere on the planet surface. They measure the mass of a 500 cm3 conical flask plus stopper as 457.23 g. after removing the air, the mass is 456.43 g (1 m3 = 1000 litres). What is the best estimate of the density of the air?
A) 0.0000016 kg/m3
B) 0.0016 kg/m3
C) 0.16 kg/m3
D) 1.6 Kg/m3

Answer 1

$1.6 kg/m^3$ is the best estimate of the density of the air on the planet.

Given:

The mass of the conical flask with stopper is 457.23 grams and the volume is $500cm^3$.

Mass of conical flask and a stopper after removing the air is 456.43 g

To find:

The density of the air on the planet.

Solution;

Mass of the conical flask and stopper with air on the planet= 457.23 g

Mass of conical flask with a stopper and without air on the planet =  456.43 g

Mass of the air in the conical flask on the planet =m

$m = 457.23 g-456.43 g=0.8 g\\\\1 g = 0.001 kg\\\\m =0.8 g =0.8\times 0.001 kg=0.0008 kg$

The volume of the conical flask = $500 cm^3$

The volume of the air in the conical flask = $V = 500cm^3$

$1 cm^3=10^{-6} m^3\\\\V= 500cm^3= 500\times 10^{-6}m^3=0.0005 m^3$

The density of the air on the planet = d

$d=\frac{m}{V}\\\\d=\frac{0.0008 kg}{0.0005 m^3}\\\\=1.6 kg/m^3$

$1.6 kg/m^3$ is the best estimate of the density of the air on the planet.

Learn more about density here:

brainly.com/question/952755?referrer=searchResults

brainly.com/question/14373997?referrer=searchResults