<h3>
Answer:</h3>
Empirical formula is CrO
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of sample of Chromium as 7.337 gram
- Mass of the metal oxide formed as 9.595 g
We are required to determine the empirical formula of the metal oxide.
<h3>Step 1 ; Determine the mass of oxygen used </h3>
Mass of oxygen = Mass of the metal oxide - mass of the metal
= 9.595 g - 7.337 g
= 2.258 g
<h3>Step 2: Determine the moles of chromium and oxygen</h3>
Moles of chromium metal
Molar mass of chromium = 51.996 g/mol
Moles of Chromium = 7.337 g ÷ 51.996 g/mol
= 0.141 moles
Moles of oxygen
Molar mass of oxygen = 16.0 g/mol
Moles of Oxygen = 2.258 g ÷ 16.0 g/mol
= 0.141 moles
<h3>Step 3: Determine the simplest mole number ratio of Chromium to Oxygen</h3>
Mole ratio of Chromium to Oxygen
Cr : O
0.141 mol : 0.141 mol
1 : 1
Empirical formula is the simplest whole number ratio of elements in a compound.
Thus the empirical formula of the metal oxide is CrO
Answer:
types of elements nacl MGS
behavior shared between atoms tranferred from one to another
properties high melting poin low melting point
example SI-o metal + non metal
example H-H only non metal elements
Explanation:
By calculating it's number of GROUP........
2 qualitative: she measures the cupcakes and finds the difference and she estimated that she would get bigger cupcakes if she put more eggs quantitive: she sees that the cupcake with 3 eggs is 0.25 centimeters taller than the cupcake with 2 eggs and she did not get any more extra cupcake even though the cupcake with 3 eggs was taller
Answer:
Binomial Naming System
Explanation:
He was the first to use the system, he used it frequently enough for the system to be accepted and used more often by scientists. He believed that species were unable to be changed.