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3 years ago

In the treatment of domestic water supplies, chlorine is added to the water to form chloric(I) acid,HClO.

1 answer:

8 0

Chlorine goes from Cl₂ to ClO⁻.

Oxidation state of Cl in Cl₂ is zero whereas in ClO⁻ it is +1. Hence change in oxidation state of Chlorine is 1.

Calculation of oxidation number of Cl in ClO⁻ or HClO⁻ :
Let x be oxidation number of Cl in ClO⁻ the. Now since the net charge on ClO⁻ is -1, sum of oxidation number of all must be equal to -1.

Therefore,
x + (-2) = -1 .....[ oxidation number of O is -2]
∴ x = 2-1 = +1
Therefore oxidation number of Cl in ClO⁻ is +1

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A sample of gas contains 6.25 × 10-3 mol in a 500.0 mL flask at 265°C. What is the pressure of the gas in kilopascals? Which var

RideAnS [48]

55.9 kPa; Variables given = volume (V), moles (n), temperature (T)

We must calculate p from V, n, and T, so we use the Ideal Gas Law:

pV = nRT

Solve for p: p = nRT/V

R = 8.314 kPa.L.K^(-1).mol^(-1)

T = (265 + 273.15) K = 538.15 K

V = 500.0 mL = 0.5000 L

∴ p = [6.25 x 10^(-3) mol x 8.314 kPa·L·K^(-1)·mol^(-1) x 538.15 K]/(0.5000 L) = 55.9 kPa

4 0

4 years ago

Read 2 more answers

Which of the following properties of water is due primarily to the uneven distribution of charge between the hydrogen and oxygen

Blizzard [7]

ability to dissolve ionic substances is the answer

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3 years ago

The standard enthalpy change for the following reaction is 873 kJ at 298 K.

Flura [38]

Answer: - 436.5 kJ.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.

The given chemical reaction is,

$2KCl(s)\rightarrow 2K(s)+Cl_2(g)$ $\Delta H_1=873kJ$

Now we have to determine the value of $\Delta H$ for the following reaction i.e,

$K(s)+\frac{1}{2}Cl_2(g)\rightarrow KCl(s)$ $\Delta H_2=?$

According to the Hess’s law, if we divide the reaction by half then the $\Delta H$ will also get halved and on reversing the reaction , the sign of enthlapy changes.

So, the value $\Delta H_2$ for the reaction will be:

$\Delta H_2=\frac{1}{2}\times (-873kJ)$

$\Delta H_2=-436.5kJ$

Hence, the value of $\Delta H_2$ for the reaction is -436.5 kJ.

8 0

3 years ago

What happens to the pressure if the gas volume is cut in half while n and I are held constant?

N76 [4]

Answer: You can use Boyle's law, which states that pressure is inversely related to volume when other variables are held constant. If the final pressure of a gas is half of the initial, the volume must double if temperature is to remain the same.

Explanation:

5 0

3 years ago

Ionic or covalent C2H5OH

Afina-wow [57]

Answer:

Covalent

Explanation:

A molecule of C₂H₅OH has C-C, C-H, C-O, and O-H bonds.

A bond between A and B will be ionic if the difference between their electronegativities (ΔEN) is greater than 1.6.

$\begin{array}{ccc}\textbf{Bond} & \textbf{$\Delta$EN} & \textbf{Polarity}\\\text{C-C} & 2.55 - 2.55 = 0.00 & \text{Nonpolar covalent}\\\text{C-H} & 2.55 - 2.20 = 0.35 & \text{Nonpolar covalent}\\\text{C-O} & 3.44 - 2.55 = 0.89 & \text{Polar covalent}\\\text{O-H} & 3.44 - 2.20 = 1.24 & \text{Polar covalent}\\\end{array}$

No bond has a large enough ΔEN to be ionic.

C₂H₅OH is a covalent molecule.

6 0

3 years ago