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xeze [42]
3 years ago
15

a bicyclist initially at rest speeds up steadily during this time interval she averages 3.50 miles per second determine the init

ial speed average speed and final speed during the time interval ​
Physics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

Explanation:

Given parameters:

Average speed  = 3.5miles per second

Unknown:

Initial speed  = ?

Average speed  = ?

Final speed in the interval = ?

Solution:

Since the bicyclist started from rest and speeds up steadily, it is correct to assume that her starting or initial speed is 0m/s.

At a state of rest, a body has no speed.

Average speed is the sum total of the speed covered at each time interval. This value is given already to be 3.5miles per second.

Final speed is the speed before the bicycle halts. This speed will be the same as the average speed here which is 3.5miles per second.

Speed is the rate of change of distance with time.

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Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.9 m tall window in 0.134 sec. From how high above th
timama [110]

Answer:

Explanation:

Given

length of window h=2.9\ m

time Frame for which rock can be seen is \Delta t=0.134\ s

Suppose h is height above which rock is dropped

Time taken to cover h+2.9 is t_1

so using equation of motion

y=ut+\frac{1}{2}at^2

where  y=displacement

u=initial velocity

a=acceleration

t=time

time taken to travel h  is

h=0+0.5\times g\times (t_2)^2---2

Subtract 1 and 2 we get

2.9=0.5g(t_1^2-t_2^2)

5.8=g(t_1+t_2)(t_1-t_2))

and from equation t_1-t_2=0.134\ s

so t_1+t_2=\frac{5.8}{9.8\times 0.134}

t_1+t_2=4.416\ s

and t_1=t_2+\Delta t

so t_2+\Delta t+t_2=4.416

2t_2+0.134=4.416

t_2=0.5\times 4.282

t_2=2.141\ s

substitute the value of t_2 in equation 2

h=0.5\times 9.8\times (2.141)^2

h=22.46\ m

                                                     

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4 years ago
Many biological systems are well-described by the laws of statistical physics. A simple yet often powerful approach is to think
GuDViN [60]

Answer:

z1/z2

Explanation:

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using the boltzman distribution the probability of finding a particle in energy state

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we have

gi to be degeneration of the ith state

ei to be energy of ith state

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P_{ope} = \frac{e^{-ei/kBt} }{z} = \frac{Z_{1} }{Z}

We have R to be equal to

\frac{P_{ope} }{P_{Close} } = \frac{Z1}{Z2}

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Which statement best describes the skier?
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25% part (c) assume that d is the distance the cheetah is away from the gazelle when it reaches full speed. Derive an expression
levacccp [35]

maximum speed of cheetah is

v_1 = v_{max}

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Answer:

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