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oee [108]
3 years ago
14

In a two-source circuit, one source acting alone produces 10 ma through a given branch. the other source acting alone produces 8

ma in the opposite direction through the same branch. the actual current through the branch is

Physics
1 answer:
pashok25 [27]3 years ago
6 0
Refer to the figure below.
R = resistance.

Case 1:
The voltage source is V₁ and the current is 10 mA. Therefore
V₁ = (10 mA)R

Case 2:
The voltage source is V₂ and the current is 8 mA. Therefore
V₂ = (8 mA)R

Case 3:
The voltage across the resistance is V₁ - V₂. Therefore the current I is given by
V₁ - V₂ = IR
10R - 8R = (I mA)R
2 = I
The current is 2 mA.

Answer: 2 mA

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Explanation:

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An Argon laser (λ = 5.0×102nm) shines down a silica glass fiber-optic cable with index of refraction 1.46. What is the speed of
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Answer:

The speed of the laser light in the cable, c_f=2.1\times 10^8\ m/s

Explanation:

It is given that,

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How much heat is released upon converting one mole of steam (18.0
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4.65 × 10⁴ Joules of heat is released upon converting one mole of steam to water.

\texttt{ }

<h3>Further explanation</h3>

Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

\large {\boxed{Q = m \times c \times \Delta t} }

<em>Q = Energy ( Joule )</em>

<em>m = Mass ( kg ) </em>

<em>c = Specific Heat Capacity ( J / kg°C ) </em>

<em>Δt = Change In Temperature ( °C )</em>

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

initial temperature of steam = t = 100.0°C

specific heat capacity of water = c = 4.186 J/gK

mass of steam = m = 18.0 gram

final temperature of water = t' = 25.0°C

specific latent heat of vaporization of water = Lv = 2268 J/g

<u>Asked:</u>

heat released = Q = ?

<u>Solution:</u>

\boxed {\large {\texttt{steam 100}^oC \overset{[Q_1]}{\rightarrow} \texttt{water 100}^oC \overset{[Q_2]}{\rightarrow} \texttt{water 25}^oC}}

Q = Q_1 + Q_2

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Q = 18.0(2268) + 18.0(4.186)(100-25)

Q = 40824 + 5651.1

Q = 46475.1 \texttt{ Joules}

Q \approx 4.65 \times 10^4 \texttt{ Joules}

\texttt{ }

<h3>Learn more</h3>
  • Efficiency of Engine : brainly.com/question/5597682
  • Flow of Heat : brainly.com/question/3010079
  • Difference Between Temperature and Heat : brainly.com/question/3821712

\texttt{ }

<h3>Answer details </h3>

Grade: College

Subject: Physics

Chapter: Thermal Physics

\texttt{ }

Keywords: Heat , Temperature , Block , Aluminium , Ice , Cold , Water

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