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Valentin [98]
3 years ago
6

An FCC iron-carbon alloy initially containing 0.20 wt% C is carburized at an elevated temperature and in an atmosphere wherein t

he surface carbon concentration is maintained at 1.0 wt%.
If after 50 h the concentration of carbon is 0.35 wt% at a position 3.5 mm below the surface, determine the temperature at which the treatment was carried out.
Engineering
1 answer:
weeeeeb [17]3 years ago
5 0

Answer:

the  temperature T at which the treatment is carried is out is  1274.24 K

Explanation:

Fick's second Law posits that the rate of change of concentration of diffusing species is directly proportional to the second derivative of the concentration.

Using the expression of the Fick's second Law:

\mathbf{\frac{C_x-C_o}{C_s-C_o} = 1- erf(\frac{x}{2\sqrt{Dt} })}

where;

C_o = initial concentration

C_x = the depth of the concentration

C_s = surface concentration

erf(\frac{x}{2\sqrt{Dt} })} = Gaussian error function.

Let variable z be used for the expression of the Gaussian error function.  erf(\frac{x}{2\sqrt{Dt} })}

Then, from the above equation:  replacing C_x with 0.35 ; C_o  with 0.2 and C_s  with 1.0; we have:

\mathbf{\frac{0.35-0.2}{1.0-0.2} = 1- erf( z)}

erf (z) = 0.8125

we obtain the error function value close to 0.8125 from the error function table and we did the  interpolation to obtain the exact value of variable  corresponding to 0.8125.

The table below shows the tabular form of the error function value close to 0.8125 .

Value for z                                                   Value for erf (z)

0.9                                                                0.797

z                                                                    0.8125

0.950                                                            0.8209  

From above; we can find  the value of variable  corresponding to the error function 0.8125 .

i.e

\frac{z-0.9}{0.95-0.9} =\frac{0.8125-0.797}{0.8209-0.797}

z = 0.932

However, the temperature dependence relation for the diffusion coefficient D can be expressed as:

z = \frac{x}{\sqrt{Dt} }

where;

z = 0.932

x = 3.5 mm = 0.0035 m

t = 50 h = 180000 sec

0.932 = \frac{0.35}{2\sqrt{D*180000} }

D = 1.958*10^{-11} m^2/s

Finally, the temperature T at which the treatment is carried is out is calculated as:

\mathbf{D=D_o \ exp \ (-\frac{Q_d}{RT}) }

From the table ‘Diffusion data’, we  obtain the values of temperature-independent pre exponential and activation energy for diffusion of carbon in FCC Fe.

D_o = 2.3*10^{-5} \ m^2/s

Q_d = 148, 000 \ J/mol

Replacing all values needed for the above equation; we have:

1.958*10^{-11}= (2.3*10^{-5})exp(\frac{-148,000}{(8.31)T})

8.51*10^{-7}=exp(\frac{-17,810}{T})

In(8.51*10^{-7})=(\frac{-17,810}{T})

-13.977 = -17,810/T

T = -17,810/ - 13.977

T = 1274.24 K

Hence, the  temperature T at which the treatment is carried is out is  1274.24 K

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3 years ago
Describe experimental factors that could be modified, and unalterable properties of materials used.
Sphinxa [80]

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a. mechanical properties

b. thermal properties

c. chemical properties

d. electical properties

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Explanation:

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b. Thermal properties such as boiling point , coefficient of thermal expansion , critical temperature  , flammability  , heat of vaporization , melting point ,thermal conductivity , thermal expansion ,triple point , specific heat capacity

c. Chemical properties such as corrosion resistance , hygroscopy , pH , reactivity , specific internal surface area , surface energy , surface tension

d. electrical properties such as capacitance , dielectric constant , dielectric strength , electrical resistivity and conductivity , electric susceptibility , nernst coefficient (thermoelectric effect) , permittivity  etc.

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3 0
3 years ago
A steam turbine operates between 500°C and 3.5 MPa to 200°C and 0.3 MPa. If the turbine generates 750 kW and the heat loss is 10
Leno4ka [110]

Answer:

1.757 kg/s

Explanation:

According to the First Law of Thermodynamics

T₁ = 500⁰C

P₁ = 3.5 Mpa

T₂ = 200⁰c

P₂ = 0.3 Mpa

W = 750 kW

Q = 100KW

M = ?

using the formula

Q - W = M (h₂ - h₁)

Q = heat loss =100 kW or 100 kJ/s

W = heat generated = 750 kW or 750 kJ/s

h₂ = specific enthalpy of superheated water leaving the turbine

    = Steam enters the turbine at 3.5 MPa and 500 degrees Celsius. From thermodynamic tables of superheated water, the value of the specific enthalpy is:

    h₂ = h₂₀₀⁰C ,0.3 Mpa = 2967.9 kJ/kg

h₁ = specific enthalpy of superheated water entering the turbine

Similarly h₁=h₅₀₀⁰C, 3.5 Mpa = 3451.7 kJ/kg

Finally, the flow rate is calculated:

in = \frac{100 - 750}{3451.7 - 2967.9} \\ = 1.757kg/s

7 0
3 years ago
A piston-cylinder device with 15 lbm of steam is heated from a temperature and pressure of 500 °F and 350 psia to a new temperat
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Answer:

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Solution:

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Mass of steam, M = 15 lbm

Temperature, T = 500^{\circ}F

Temperature, T' = 600^{\circ}F

Pressure, P = 350 psia

Since, the process results in the change in volume at constant pressure.

Now, work done by the steam is given by;

W = \int_{V}^{V'} P dU

And

U = mV

So,

W = m\int_{V}^{V'} P dV

W = mP(V' - V)           (1)

Now, using the super heated vapor table:

At 350 psia and 500^{\circ}F,  V = 1.5 ft^{3}/lb

At 350 psia and 600^{\circ}F,  V' = 1.7 ft^{3}/lb

Now, using these values in eqn(1):

W = 15\times 350(1.7 - 1.5) = 1050 Btu

4 0
3 years ago
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