Use the conservation of the momentum to answer this question:
The resulting speed of the two bodies will be 2.2 m/s in the (original) direction of the overweight guy (110kg). Their brains not happy about the collision either.
Answer:
v_f = -25.9 m/s
Explanation:
- The complete question is as follows:
" Assume that a pitcher throws a baseball so that it travels in a straight line parallel to the ground. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. Define the direction the pitcher originally throws the ball as the +x direction.
Now assume that the pitcher in Part D throws a 0.145-kg baseball parallel to the ground with a speed of 32 m/s in the +x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. What is the ball's velocity just after leaving the bat if the bat applies an impulse of −8.4N⋅s to the baseball?"
Given:
- mass of baseball m = 0.145 kg
- Speed before impact v_i = 32 m/s
- Speed after impact v_f
- Impulse applied by the bat I = - 8.4Ns
Find:
What is the ball's velocity just after leaving the bat
Solution:
- Impulse is the change in linear momentum of the ball according to Newton's second law of motion:
I = m* ( v_f - v_i )
- Taking the + from pitcher to batsman and - from batsman to pitcher.
- Plug in the values:
-8.4 = 0.145* ( v_f - (32) )
v_f = -57.93103 + 32
v_f = -25.9 m/s
The answer is b. All you have to do is find the intercepts.
Answer:
t = 3.94 s
Explanation:
This can be modeled as a case of free fall motion. Because, the falcon is going down with acceleration, that is equal to acceleration due to gravity. To find the time taken by the falcon to intercept the pigeon, we will use second equation of motion for vertical direction:
where,
h = height = 76 m
vi = initial speed of falcon = 0 m/s
t = time required = ?
g = acceleration due to gravity = 9.81 m/s²
Therefore,
<u>t = 3.94 s</u>
