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Anna71 [15]
2 years ago
10

Which of the graphs describes the motion of a person who first rode her bicycle at constant speed and then rested?

Physics
1 answer:
sergeinik [125]2 years ago
5 0

Answer:

Its graph 1

Explanation:

She started at the origin and kept riding her bike until she stopped which causes the line to go staright because she's not moving.

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Hannah drove 360 mi in 5.2 hours. What was her average speed?
ANTONII [103]
Her average speed would be 69.2 miles per hour

Explanation:
When you take the number of miles and divide it by the number of hours you get 69.2 (when rounded)
That is how fast she went per hour
5 0
3 years ago
How do you test hydrogen gas
Vanyuwa [196]

Explanation:

A splint is lit and held near the opening of the tube, then the stopper is removed to expose the splint to the gas. If the gas is flammable, the mixture ignites. This test is most commonly used to identify hydrogen, which extinguishes with a distinctive 'squeaky pop' sound.

3 0
3 years ago
Read 2 more answers
A 100-m-long wire carrying a current of 4.0 A will be accompanied by a magnetic field of what strength at a distance of 0.050 m
solong [7]

Answer:

1.6 x 10^-5 T

Explanation:

i = 4 A

r = 0.05 m

The magnetic field due to long wire at a distance r is given by

B = \frac{\mu _{0}}{4\pi }\times \frac{2i}{r}

B = 10^-7 x 2 x 4 / 0.05

B = 1.6 x 10^-5 T

3 0
3 years ago
Food chains are made up of many_____________. HELP ASAP!!!!!
Mashcka [7]
Hello!

Possible answer could be Organisms

There are a lot of Organisms in the overall food chain.

Hope this helped!
4 0
3 years ago
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Find the position of the center of mass of the system of the sun and Jupiter? (Since Jupiter is more massive than the rest of th
8090 [49]

Answer:

r_{cm} = 0.074 m from the position of the center of the Sun

Explanation:

As we know that mass of Sun and Jupiter is given as

M_s = 1.98 \times 10^{30} kg

M_j = 1.89 \times 10^{27} kg

distance between Sun and Jupiter is given as

r = 7.78 \times 10^{11} m

now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them

so we will have

r_{cm} = \frac{M_s r_1 + M_j r_2}{M_s + M_j}

r_{cm} = \frac{1.98 \times 10^{30} (0) + (1.89 \times 10^{27})(7.78 \times 10^{11})}{1.98 \times 10^{30} + 1.89 \times 10^{27}}

r_{cm} = 0.074 m from the position of the center of the Sun

3 0
3 years ago
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