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Anna71 [15]
2 years ago
10

Which of the graphs describes the motion of a person who first rode her bicycle at constant speed and then rested?

Physics
1 answer:
sergeinik [125]2 years ago
5 0

Answer:

Its graph 1

Explanation:

She started at the origin and kept riding her bike until she stopped which causes the line to go staright because she's not moving.

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An open cart is rolling to the left on a horizontal surface. A package slides down a chute and lands in the cart. Which quantity
Marat540 [252]

Answer: the horizontal component of total momentum

Explanation:

Since the open cart is rolling to the left on the horizontal surface, the quantity that has the same value just before and just after the package lands in the cart is the horizontal component of total momentum.

Momentum, is the product of the mass of a particle and the velocity of the particle. The change of momentum depends on the force which acts on it. The addition of the the individual momenta is the total momentum.

8 0
2 years ago
A cannon ball is fired directly upward with a velocity of 160 m/s. How long does it take to fall back to the ground? s How fast
Andrej [43]
To answer this problem, we will use the equations of motions.

Part (a):
For the ball to start falling back to the ground, it has to reach its highest position where its final velocity will be zero.
The equation that we will use here is:
v = u + at where
v is the final velocity = 0 m/sec
u is the initial velocity = 160 m/sec
a is acceleration due to gravity = -9.8 m/sec^2 (the negative sign is because the ball is moving upwards, thus, its moving against gravity)
t is the time that we want to find.
Substitute in the equation to get the time as follows:
v = u + at
0 = 160 - 9.8t
9.8t = 160
t = 160/9.8 = 16.3265 sec
Therefore, the ball would take 16.3265 seconds before it starts falling back to the ground

Part (b):
First, we will get the total distance traveled by the ball as follows:
s = 0.5 (u+v)*t
s = 0.5(160+0)*16.3265
s = 1306.12 meters
The equation that we will use to solve this part is:
v^2 = u^2 + 2as where
v is the final velocity we want to calculate
u is the initial velocity of falling = 0 m/sec (ball starting falling when it reached the highest position, So, the final velocity in part a became the initial velocity here)
a is acceleration due to gravity = 9.8 m/sec^2 (positive as ball is moving downwards)
s is the distance covered = 1306.12 meters
Substitute in the above equation to get the final velocity as follows:
v^2 = u^2 + 2as
v^2 = (0)^2 + 2(9.8)(1306.12)
v^2 = 25599.952 m^2/sec^2
v = 159.99985 m/sec
Therefore, the velocity of the ball would be 159.99985 m/sec when it hits the ground.
6 0
3 years ago
Why are the coldest places on earth found near the poles
Nata [24]
Polar regions do not receive direct sunlight during the winter months due to the tilt in the Earth's<span> axis. Hence, polar regions can get very cold. Antarctica is the </span>coldest place on Earth. <span>The </span>coldest places on Earth<span> tend to be located </span>near the poles<span>. Hope this answers the question.</span>
6 0
3 years ago
Gaussian surfaces A and B enclose the same positive point charge. The area of surface A is two times larger than that of surface
svlad2 [7]

Answer:

The total electric flux through the two surfaces is equal.

Explanation:

6 0
3 years ago
When a golfer tees off, the head of her golf club, which has a mass of 160 g, is traveling 50 m/s just before it strikes a 46 g
olya-2409 [2.1K]

Answer:

v1=21.81m/s

Explanation:

<em>When a golfer tees off, the head of her golf club, which has a mass of 160 g, is traveling 50 m/s just before it strikes a 46 g golf ball at rest on a tee. Immediately after the collision, the club head continues to travel in the same direction but at a reduced speed of 44 m/s. Neglect the mass of the club handle and determine the speed (in m/s) of the golf ball just after impact.</em>

According to the law of conservation of momentum, if the net external force on a system is zero, then the linear momentum of the system is conserved.

During collision of two particles, the external force on the system of two colliding particles is zero (only internal force acts between the colliding particles), therefore, the momentum is conserved during the collision.

Answer and Explanation:

Given :

head of the golf club=160g

velocity of the golf club=50 m/s

golf ball mass=46g

velocity=om/s

m1u1+m2u2=m1v1+m2v2.........................................1

160*50 +46*0=160*44+46*v1

8000=7040+46v1

960=46v1

v1=960/46

v1=21.81m/s

3 0
3 years ago
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