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Anna71 [15]
3 years ago
10

Which of the graphs describes the motion of a person who first rode her bicycle at constant speed and then rested?

Physics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

Its graph 1

Explanation:

She started at the origin and kept riding her bike until she stopped which causes the line to go staright because she's not moving.

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In your own words, explain what a field is in science. Use specific examples to support your explanation.
tresset_1 [31]

Answer:

Field, In physics, a region in which each point is affected by a force.

Explanation:

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3 years ago
: Do you attract the Earth or the Earth attracts you which one is attracting with a larger force?
seraphim [82]

Answer: The Earth and you are attracted to the centers of each other by a pair of equal gravitational forces. The size of the force attracting you toward the center of the Earth is your "weight" on Earth. The size of the force attracting the Earth toward the center of you is the Earth's "weight" on you.

Explanation:

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A deuteron, 21H, is the nucleus of a hydrogen isotope and consists of one proton and one neutron. The plasma of deuterons in a n
Naddik [55]

Answer:

1917723.40119 m/s

Explanation:

m = Mass of deuteron = (1.637+1.675)\times 10^{-27}=3.312\times 10^{-27}

k = Boltzmann constant = 1.381\times 10^{-23}\ J/K

T = Temperature = 2.94\times 10^8\ K

RMS velocity is given by

V_r=\sqrt{\dfrac{3kT}{m}}\\\Rightarrow V_r=\sqrt{\dfrac{3\times 1.381\times 10^{-23}\times 2.94\times 10^8}{3.312\times 10^{-27}}}\\\Rightarrow V_r=1917723.40119\ m/s

The RMS velocity of the deutrons is 1917723.40119 m/s

8 0
3 years ago
A) Jaką długość powinien mieć mieć bok kwadratu , aby pole tego kwadratu było równe polu prostokątu o wymiarach 3cm x 4
seropon [69]
What do you even mean..
5 0
3 years ago
A uniform disk with a mass of 5.0 kg and diameter 30 cm rotates on a frictionless fixed axis through its center and perpendicula
Marina86 [1]

Answer:\alpha =10.66 rad/s^2

Explanation:

Given

mass of disk m=5 kg

diameter of disc d=30 cm

Force applied F=4 N

Now this force will Produce  a  torque of magnitude

T=F\cdot r

T=4\dot 0.15

T=0.6 N-m

And Torque is given Product of moment of inertia and angular acceleration (\alpha )

T=I\cdot \alpha

Moment of inertia for Disc I= \frac{Mr^2}{2}

I=0.05625 kg-m^2

0.6=0.05625\cdot \alpha

\alpha =10.66 rad/s^2

3 0
3 years ago
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