Answer:
11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.
Explanation:
Chloroacetic acid is an monoprotic acid.
Neutralization reaction: 
So, 1 mol of chloroacetic acid is neutralized by 1 mol of NaOH.
Molar mass of chloroacetic acid = 94.5 g/mol
So, 0.154 g of chloroacetic acid =
moles of chloroacetic acid
= 0.00163 moles of chloroacetic acid
Lets assume V mL of 0.1400 M of NaOH is required to reach equivalence point.
So, number of moles of NaOH needed to reach equivalence point
=
moles
So, 
or, V = 11.6
Hence, 11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.