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Semenov [28]
10 months ago
6

Give the group number and general electron configuration of an element with each electron-dot symbol:

Chemistry
1 answer:
MatroZZZ [7]10 months ago
4 0

The group number of (a) is VA(15) and electronic configuration is 1s2 2s2 2p3 . the group number of (b) is IVA(14) and the electronic configuration is 1s2 2s2 2p2 .

What is electronic configuration ?

it shows the distribution of electrons in the atomic orbitals .  

it follows a standard notation of s, p, d, f atomic orbitals in which electronic distribution of an atom occurs .

it has standard notation method as well as condensed electron configuration .

it is useful in determining the valency of an element .

it is useful in predicting the properties of a group of elements .

<h3>What is condensed electron configuration ?</h3>

It contains the symbol of the nearest , smaller noble gas in the square brackets and then the symbols of the occupied orbitals which contains valance electrons .

Example of condensed electron configuration is given by ,

in case of iron the electronic configuration is 1s2 2s2 2p6 3s2 4s2 3d6 .

Thus , the condensed electron configuration of iron is [Ar] 3d6 4s2 .

Learn more about electronic configuration here :

brainly.com/question/50903246

#SPJ4

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PLEASE HELP- I WILL GIVE BRAINLIEST AND THANKS
julsineya [31]

Answer:

The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams

Explanation:

The question is with regards to density calculations

The density of the given sodium carbonate solution, ρ = 0.4 g/dm³

The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³

Density \ of \ an \ object, \rho  = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }

\rho = \dfrac{m}{V}

Therefore, we have;

The \ Density \ of \ the \ sodium \ carbonate, \ \rho  = 0.4 \ g/dm^3 =  \dfrac{m }{ 0.01 \ dm^3 }

The mass, "m", of the sodium carbonate in  = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g

The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.

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