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Semenov [28]
1 year ago
6

Give the group number and general electron configuration of an element with each electron-dot symbol:

Chemistry
1 answer:
MatroZZZ [7]1 year ago
4 0

The group number of (a) is VA(15) and electronic configuration is 1s2 2s2 2p3 . the group number of (b) is IVA(14) and the electronic configuration is 1s2 2s2 2p2 .

What is electronic configuration ?

it shows the distribution of electrons in the atomic orbitals .  

it follows a standard notation of s, p, d, f atomic orbitals in which electronic distribution of an atom occurs .

it has standard notation method as well as condensed electron configuration .

it is useful in determining the valency of an element .

it is useful in predicting the properties of a group of elements .

<h3>What is condensed electron configuration ?</h3>

It contains the symbol of the nearest , smaller noble gas in the square brackets and then the symbols of the occupied orbitals which contains valance electrons .

Example of condensed electron configuration is given by ,

in case of iron the electronic configuration is 1s2 2s2 2p6 3s2 4s2 3d6 .

Thus , the condensed electron configuration of iron is [Ar] 3d6 4s2 .

Learn more about electronic configuration here :

brainly.com/question/50903246

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an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
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Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

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