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3 years ago

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1. If the frequency of a wave increases from 2 Hz to 4 Hz without the wavelength changing, how will the wave speed change? PLS H

ELP!!!! WILL MARK BRAINLIST!!!!!!!

1 answer:

kolezko [41]3 years ago

5 0

Answer:

biraz naruto izle

Explanation:

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When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at

STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

$1.22 * 10^{5} = - 8.314* 2400 * ln K$

$\\ 1.22 * 10^{5} = -19953.6 * ln K$

$ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022$

So, the equilibrium constant is 0.0022.

4 0

3 years ago

8.38e-21 Q^2 -1.07e-23 Q^2 +3.15e+19<br> Solve for Q

GarryVolchara [31]

8.38e -21Q^2 -1.07e -23Q^2 +3.15e +19
= 10.46e -44Q^2 + 19
44Q^2 = 10.46e + 19
Q^2 = 523/2200e + 19/44
Q1= ≈ -1.03828
Q2= ≈ 1.03828

4 0

4 years ago

(d) If you have 9.44 g of NazPO4, how many grams of AgNO, will be needed for complete

AlladinOne [14]

30.6 g of AgNO₃

Explanation:

We have the following chemical reaction:

Na₃PO₄ + 3 AgNO₃ → Ag₃PO₄ + 3 NaNO₃

Now we calculate the number of moles of Na₃PO₄:

number of moles = mass / molecular weight

number of moles of Na₃PO₄ = 9.44 / 164 = 0.06 moles

Now we formulate the following reasoning:

if 1 mole of Na₃PO₄ will react with 3 moles of AgNO₃

then 0.06 moles of Na₃PO₄ will react with X moles of AgNO₃

X = (0.06 × 3) / 1 = 0.18 moles of AgNO₃

mass = number of moles × molecular weight

mass of AgNO₃ = 0.18 × 170 = 30.6 g

Learn more about:

mole concept

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3 0

3 years ago

How many grams of LiNO2 are required to make 250 mL of 0.75 Molarity solution?

Katarina [22]

Answer:

159 g OF LiNO2 WILL BE USED TO MAKE 0.25 L OF 0.75 M SOLUTION.

Explanation:

How many grams of LiNO2 are required to make 250 mL of 0.75 M?

First calculate the molarity in mol per dm3

0.75 M of LiNO2 reacts in 250 mL = 250 /1000 L volume

0.75 M = 0.25 L

In 1 L, the molarity of LiNO2 will be:

= (0.75 * 1/ 0.25) M

= 3 mol/dm3 of LiNO2

Next is to calculate the molarity in g/dm3:

Molarity in mol/dm3 = molarity in g/dm3 / RMM.

RMM of LiNO2

(Li = 7 , N =14 , 0 = 16)

RMM = ( 7 + 14 + 16 * 2) = 53 g/mol

Molarity in mol/dm3 = Molarity in g/dm3 / RMM

Molarity in g/dm3 = Molarity in mol/dm3 * RMM

Molarity in g/dm3 = 3 * 53

Molarity in g/dm3 = 159 g/dm3.

So therefore, to make 250 mL of 0.75 M of LiNO2, we use 159 grams of LiO2.

8 0

3 years ago

True or false for the following questions?

WARRIOR [948]

Answer:

T

F

T

Explanation:

hope it helps! sorry for no explanation

3 0

3 years ago