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nlexa [21]
3 years ago
15

Average speed is useful but it might not describe your actual speed

Physics
1 answer:
gregori [183]3 years ago
6 0
Average speed is useful in describing the motion of a body, but it does not tell everything about the motion. For instance, a car traveling at an average speed of 100 kilometers per hour during a certain hour could conceivably have traveled at 150 km/h for 40 minutes, Energy, Ch. 3, extension 1 Calculating average speed and velocity 3 then halted for the last 20 minutes as a patrolman gave the driver a ticket (picture above). Its average speed really does not describe that hour’s journey very well. The way to deal with such a situation is to take the average over a shorter interval, and do this more times. In the example given above, if the speed were sampled every 15 minutes instead of over the entire hour, we would list average speeds of 150 km/h at the start (0 to 15 minutes), 150 km/h (15 to 30 minutes), 100 km/h (30 to 45 minutes), and 0 km/h (45 to 60 minutes).
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Name 2 common methods of polymerization.
navik [9.2K]

Answer: Addition polymerization & Condensation polymerization

6 0
3 years ago
Marc attaches a falling 500-kg object with a rope through a pulley to a paddle wheel shaft. He places the system in a well-insul
Klio2033 [76]

Answer:

4.68227 °C

Explanation:

m_o = Mass of object = 500 kg

m_w = Mass of water = 25 kg

c = Specific heat of water at 20°C = 4186 J/kg°C

h = Height from which the object falls = 100 m

g = Acceleration due to gravity = 9.8 m/s²

The potential energy and heat will balance each other

PE=Q\\\Rightarrowmc m_ogh=m_oc\Delta T\\\Rightarrow \Delta T=\frac{m_ogh}{m_oc}\\\Rightarrow \Delta T=\frac{500\times 9.8\times 100}{25\times 4186}\\\Rightarrow \Delta=4.68227\ ^{\circ}C

The temperature change in the water is 4.68227 °C

5 0
4 years ago
You have 1.2kg of (AU)gold (that's quite a bit of money at $1839/ounce). Using a heat source you apply 3096 J to the gold and re
melamori03 [73]

Answer:

129 J/Kg°C

Explanation:

Given :

Mass of gold, m = 1.2kg

Quantity of heat applied, Q = 3096 J

Temperature, t2 = 40°C

Temperature, t1 = 20°C

Change in temperature, dt = (40-20)°C = 20°C

Using the relation :

Q = mcdt

Where, C = specific heat capacity of gold

3096 = 1.2kg * C * 20°C

3096 J = 24kg°C * C

C = 3096 J / 24 kg°C

C = 129 J/Kg°C

7 0
3 years ago
A certain type of laser emits light that has a frequency of 4.2 × 1014 Hz. The light, however, occurs as a series of short pulse
bogdanovich [222]

Explanation:

It is given that,

Frequency of the laser light, f=4.2\times 10^{14}\ Hz

Time, t=3.2\times 10^{-11}\ s

(a) Let \lambda is the wavelength of this light. It can be calculated as :

\lambda=\dfrac{c}{f}

\lambda=\dfrac{3\times 10^8}{4.2\times 10^{14}}

\lambda=7.14\times 10^{-7}\ m

or

\lambda=714\ nm

(b) Let n is the number of the wavelengths in one pulse. It can be calculated as :

n=f\times t

n=4.2\times 10^{14}\times 3.2\times 10^{-11}

n = 13440

Hence, this is the required solution.

8 0
3 years ago
PSYCHOLOGY! A _________ is a graphical representation of association between variables.
pshichka [43]

Answer:

A. Scatterplot

Explanation:

because it is

5 0
3 years ago
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