If the rifle is stopped by the hunter’s shoulder in a distance of 3.16 cm, what is the magnitude of the average force exerted on
2 answers:
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Answer:
The speed of the electron is .
Explanation:
Given that,
The magnitude of electric field,
The magnitude of magnetic field, B = 0.516 T
Both the magnetic and electric fields are acting on the moving electron. Then, the magnitude of electric field and magnetic field is balanced such that :
or
So, the speed of the electron is . Hence, this is the required solution.
The intensity of the magnetic force F experienced by a charge q moving with speed v in a magnetic field of intensity B is equal to
where
is the angle between the directions of v and B.
1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is
. In this case, v and B are perpendicular, so 
, therefore we have:
2) In this second case, the angle between v and B is
. The charge is now 
, and the magnetic field is the one we found in the previous part, B=2.8 T, so we can find the intensity of the force experienced by this second charge:
where
1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is
2) In this second case, the angle between v and B is