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STALIN [3.7K]
3 years ago
14

A) Find the displacement for the given time intervals ,

Physics
2 answers:
klasskru [66]3 years ago
6 0

Answer:

the answer is that it will be positive

Olegator [25]3 years ago
3 0

Answer:

hahsususisjsbsb

Explanation:

vsgshzjdjdk

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What are three elements that are in the same group
cluponka [151]
Iodine, chloride, and bromide
3 0
2 years ago
Multiply 5.036×102m by 0.078×10−1, taking into account significant figures.
Anika [276]

Answer : The significant digit is 6

Explanation :

Multiply 5.036\times10^{2}m by 0.078\times10^{-1}m

Now, on multiplying

5.036\times10^{2}m \times0.078\times10^{-1}m = 0.392808 \times10^{1}\ m^{2}

5.036\times10^{2}m \times0.078\times10^{-1}m = 0.0392808\ m^{2}

Now, the significant digit is 6.

Hence, this is the required solution.

3 0
3 years ago
The volume of a gas at 400.0ml when the pressure is 1.00atm. at the same temperature, what is the pressure at which the volume o
Mila [183]

Answer:

5.025 atm

Change the 2.01 to ml then cross multiply

400/1= 2010/x

210/400=5.025

3 0
3 years ago
a car whose mass is 1000kg is traveling at a constant speed of 10m/s. Neglecting any friction how much force will the engine hav
AURORKA [14]
This next statement is a big deal.  It should be up on a board, surrounded
by flashing red and yellow lights, and hung on the wall of every Science
classroom.   Although we never see it in our daily lives, it's fundamental to
the workings of the universe, and it's also Newton's first law of motion:

<em>Without friction, it doesn't take <u>ANY</u> force to keep a moving object
moving.  </em>
<em>Force is only required to <u>change</u> the object's speed, or to
<u>change</u> the direction </em>
<em>in which it's moving.</em>

The answer to the question is:  On a level road, and neglecting any friction,
the engine doesn't have to supply ANY force to keep the car going at the
same speed.
7 0
3 years ago
Read 2 more answers
A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result
Over [174]
B) law of conservation of momentum

It states that the total momentum of a system before impact is the same as the total momentum of the system after impact.

In this case total momentum before impact:

10kg*5m/s  + 5kg * 0m/s = 50 kg m/s

After Impact:

10kg*0m/s + 5kg*10m/s = 50 kg m/s

You can see the momentum before and after impact is same as 50 kg m/s  

Of course we assumed that the first cart stopped after the impact, and there are no energy losses.
7 0
3 years ago
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