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STALIN [3.7K]
3 years ago
14

A) Find the displacement for the given time intervals ,

Physics
2 answers:
klasskru [66]3 years ago
6 0

Answer:

the answer is that it will be positive

Olegator [25]3 years ago
3 0

Answer:

hahsususisjsbsb

Explanation:

vsgshzjdjdk

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car 2 has a mass of 150 kg and moves westward towards car 3 at a velocity of 2.2 m/s. car 3 has a mass of 265 kg and moves eastw
sergejj [24]

Answer:

The force of car 3 on car 2 ≈ 1810.82 N

Explanation:

The equation for the change in momentum of the two cars are;

Conservation of linear momentum

150( 2.2 - v) = 265(1.5-v)

150 × 2.2 - 265×1.5 = (150+265)v

150 × 2.2 - 265×1.5 = -67.5 = 415×v

∴ v = -67.5/415 = -0.1627 m/s West = 0.1627 m/s East

The impulse of the net force is the amount of momentum change experienced given by the equation;

Impulse force = m \times  v_f - m \times  v_0

Where;

v_f = The final velocity

v_0 = The initial velocity

For the the 265 kg mass, we have;

v_f = 0.1627 m/s

v_0 = 1.5 m/s

Which gives the impulse a s F×Δt =  265×0.1627 - 265×1.5 = -354.38 kg·m/s

The change in kinetic energy of the collision = 1/2×265×(0.1627^2 - 1.5^2) =-294.62 J

Whereby the distance moved in one second is 0.1627 m, we have;

Work done = Force × Distance = Force × 0.1627 = 294.62

Force = 294.62/0.1627 = 1810.82 N.

8 0
3 years ago
What is another name for kidney stones?
Naddika [18.5K]

Another (slightly more technical) name for kidney stones is "renal calculus".

I know this because we have met many times, and we are old friends.


8 0
3 years ago
Read 2 more answers
What is the acceleration of an object with a mass of 15 kg and a coefficient of friction of 0.18
11111nata11111 [884]

Answer:

a = 1.764m/s^2

Explanation:

By Newton's second law, the net force is F = ma.

The equation for friction is F(k) = F(n) * μ.

In this case, the normal force is simply F(n) = mg due to no other external forces being specified

F(n) = mg = 15kg * 9.8 m/s^2 =  147N.

F(k) = F(n) * μ = 147N * 0.18 = 26.46N.

Assuming the object is on a horizontal surface, the force due to gravity and the normal force will cancel each other out, leaving our net force as only the frictional one.

Thus, F(net) = F(k) = ma

26.46N = 15kg * a

a = 1.764m/s^2

7 0
3 years ago
A 34.00 kg sample of mud has a specific heat of 2,512 J/kg °C.
Elena-2011 [213]

Answer:

B ig lol

Explanation:

6 0
3 years ago
The resistance of a conductor depends on all of the following, except _____.
borishaifa [10]
Hello There!

The resistance of a conductor depends on all of the following except mass.
Mass wouldn't affect the resistance in any way.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
5 0
3 years ago
Read 2 more answers
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