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STALIN [3.7K]
3 years ago
14

A) Find the displacement for the given time intervals ,

Physics
2 answers:
klasskru [66]3 years ago
6 0

Answer:

the answer is that it will be positive

Olegator [25]3 years ago
3 0

Answer:

hahsususisjsbsb

Explanation:

vsgshzjdjdk

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A 4350 kg truck, driving 7.39 m/s, runs into the back of a stationary car. After the collision, the truck moves 4.55 m/s and the
DiKsa [7]

Answer:

Mass of car = 1098 kg

Explanation:

Here law of conservation of momentum is applied.

Let mass of car be m.

Initial momentum = Final momentum.

Initial momentum = 4350 x 7.39 + m x 0 = 32416.5 kgm/s

Final momentum = 4350 x 4.55 + m x 11.5 = 19792.5+11.5m

We have

      19792.5+11.5m = 32416.5

        m = 1097.97 kg

Mass of car = 1098 kg

4 0
3 years ago
How do vibrations cause sound waves
Mariulka [41]
 <span>sound waves are a type of wave sometimes called compression waves, vibrations with enough of an amplitude can compress and decompress the air adjacent to the object causing the waves to form.</span>
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3 years ago
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What is the sun? I'm really confused and we are studying the solar system please help?
stellarik [79]
The sun is a star (a giant ball of burning gases).
4 0
3 years ago
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Atoms that have become negatively charged by gaining extra electrons are called _____. anions anodes cations cathodes
nikklg [1K]
Anions: negatively charged atoms

Cations: positively charged atoms (CAT-ions are PAWS-itively charged)
Anode: positively charged electrode that allows electrical current flow (positive end of battery)
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2 years ago
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A diffraction grating produces a first-order bright fringe that is 0.18 m away from the central bright fringe on a flat screen.
Georgia [21]

Answer:

The wavelength of the light is 562.5 nm

Solution:

As per the question:

Order, n = 1

Slit separation, d = 2.5\times 10^{- 6}\ m

Distance from the bright fringe, y = 0.18 m

Distance between the screen and the grating, D = 0.8 m

Now,

We know from the eqn for diffraction:

n\lambda = dsin\theta

n = 1

\lambda = dsin\theta            (1)

Also,

For very small angle, \theta:

sin\theta ≈ tan\theta = \frac{y}{D} = \frac{0.18}{0.8} = 0.225

Using the above value in eqn (1):

\lambda = 2.5\times 10^{- 6}\times 0.225 = 5.625\times 10^{- 7}\ m = 562.5\ nm

3 0
2 years ago
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