Answer:
22.1g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaO + 2NaCl —> Na2O + CaCl2
Next, we shall determine the mass of CaO that reacted and the mass of Na2O produced from the balanced equation.
This is illustrated below:
Molar mass of CaO = 40 + 16 = 56g/mol
Mass of CaO from the balanced equation = 1 x 56 = 56g
Molar mass of Na2O = (23x2) + 16 = 62g/mol
Mass of Na2O from the balanced equation = 1 x 62 = 62g
From the balanced equation above,
56g of CaO reacted to produce 62g of Na2O.
Finally, we can determine the theoretical yield of Na2O as follow:
From the balanced equation above,
56g of CaO reacted to produce 62g of Na2O.
Therefore, 20g of CaO will react to produce = (20 x 62)/56 = 22.1g of Na2O.
Therefore, the theoretical yield of Na2O is 22.1g
