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Anika [276]
3 years ago
6

Salicylic acid (C7H6O3) reacts with acetic anhydride (C4H6O3) to form acetylsalicylic acid (C9H8O4). 2C7H6O3(aq) + C4H6O3(aq) mc

002-1.jpg 2C9H8O4(aq) + H2O(l) What is the limiting reactant if 70.0 g of C7H6O3 and 80.0 g of C4H6O3 react?
Chemistry
2 answers:
olga nikolaevna [1]3 years ago
3 0
In order to understand what is the limiting reactant is useful to convert the masses of reactants into moles. The molecular masses are:

C_7H_6O_3 = 138\frac{g}{mol}\\ C_4H_6O_3 = 100\frac{g}{mol}

Converting masses into moles:

70\g \C_7H_6O_3\cdot \frac{1\ mol}{138\ g} = 0.5\ mol\ C_7H_6O_3

80\ g\ C_4H_6O_3\cdot \frac{1\ mol}{100\ g} = 0.8\ mol\ C_4H_6O_3

In the reaction, 2 moles of C_7H_6O_3 are necessary to react with 1 mol of C_4H_6O_3. Following this ratio:

0.8\ mol\ C_4H_6O_3\cdot \frac{2\ mol\ C_7H_6O_3}{1\ mol\ C_4H_6O_3} = 1.6\ mol\ C_7H_6O_3

We have only 0.5 mol of C_7H_6O_3, i.e, we don't have enough amount of salicylic acid, therefore, this is the limiting reactant.
ololo11 [35]3 years ago
3 0

Answer: B) Salicylic acid

Explanation: i just took the test !!!!!

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PLEASE HELP!!! NEED TO PASS THIS TO THE FIRST SEMESTER!
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Answer:

Reaction 1 is balanced but 2 is not balanced , the balance equation are :

1. CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)

2.CaCl_{2}(aq) + 2NaHCO_{3}(aq)\rightarrow CaCO_{3}(aq) + H_{2}O(l) + 2NaCl(aq) + H_{2}O(aq)

Explanation:

Balanced Equations : These are the equation which follows the law of conservation of mass .

The total number of atoms present in reactant is equal to total number of atoms present in product.

1. CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)

This is acid - base type reaction where

CH_{3}COOH(aq) act as Acid

NaHCO_{3}(aq) act as weak base

Reactant :CH_{3}COOH(aq) ,NaHCO_{3}

Number of atoms of :

C = 2 (CH_{3}COOH(aq)) + 1 (NaHCO_{3})

   = 2 + 1

   = 3

H  = 4(CH_{3}COOH(aq)) + 1 (NaHCO_{3})

     = 4 + 1

       5

O = 2(CH_{3}COOH(aq)) + 3 (NaHCO_{3})

    = 5

Na = 1 (NaHCO_{3})

     = 1

Product :  CO_{2}(g),H_{2}O(l) , CH_{3}COONa(aq)

Number of atoms :

C = 1(CO_{2}(g)) + 2(CH_{3}COONa(aq))

   = 1 + 2

   = 3

H = 2(H_{2}O(l)) + 3(CH_{3}COONa(aq))

   = 2 + 3

   = 5

O = 1(H_{2}O(l)) + 2(CH_{3}COONa(aq))

        +2(CO_{2}(g)

    = 1 + 2 + 2

    = 5

Na = 1(CH_{3}COONa(aq)

     = 1

Number of Na =1 , C = 3 , H= 5 and O =5 in both reactant and product , so it is a balanced reaction

2.CaCl_{2}(aq) + 2NaHCO_{3}(aq)\rightarrow CaCO_{3}(aq) + H_{2}O(l) + 2NaCl(aq) + CO_{2}(g)

This is double displacement reaction .

Check the balancing in both reactant and products should be :

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H = 2

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