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goldfiish [28.3K]
3 years ago
6

How many grams are there in 7.4 x 10^23 molecules of AgNO3?

Chemistry
1 answer:
mr_godi [17]3 years ago
4 0

Data we are collecting from the equation as:

7.4x10^23 = silver nitrate molecules as given from question.

As we know avogandro'S no. 6.022*1023 which is number of molecules.

So when we calculate any no. Of mole of any atom we know that 1mole of any atom is equal to avogandro'S no and grams can be calculate from moles equation.

So back to point,

Dividing molecules of AgNO3 to no. of molecules per mol of AgNO3

7.4 / 6.02*1023

= 1.229*1023per mole of AgNO3.

OK we get the moles of AgNO3

Now checking the gram of AgNO3

Weight of AgNO3 is 163.868.

Now multiplying both values moles*molar weight of AgNO3

1.229*1023 * 763.868 = 208.767grams of AgNo3

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Explanation:

The number of moles of solute is equal to product of the molar concentration (molarity) and the volume (in liters) of solution.

Since the volumes and the molar concentrations of the<em> NaOH </em>and <em>HCl </em>solutions mixed are equal, each one of them contributes the same number of moles of solute.

Since every mol of NaOH produces one mol of OH⁻ ions and every mol of HCl produces one mol of H⁺ ion, the number of moles of OH ⁻ and H⁺ in solution are equal.

Thus, OH⁻ and H⁺ ions will be neutralized by the reaction:

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6 0
4 years ago
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Explanation:

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6 0
3 years ago
What mass of potassium chloride, KCl, is produced when 12.6 g of oxygen, 02, is produced?
blagie [28]

Mass of KCl= 19.57 g

<h3>Further explanation</h3>

Given

12.6 g of Oxygen

Required

mass of KCl

Solution

Reaction

2KClO3 ⇒ 2KCl + 3O2

mol O2 :

= mass : MW

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From the equation, mol KCl :

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