A spherically spreading EM wave comes from an 1800-W source. At a distance of 5.0 m, what is the intensity, and what is the rms
1 answer:
Answer:
The intensity of the EM wave is 5.729 W/m²
The rms value of the electric field is 46.452 V/m
Explanation:
Given;
power of the electromagnetic wave, P = 1800 W
The intensity of light is given by;
I = P / A
Where;
A is the surface area of the sphere = 4πr²
A is the surface area of the sphere = 4π(5)²
A is the surface area of the sphere = 314.2 m²
The intensity is calculated as;
I = P / A
I = (1800) / (314.2)
I = 5.729 W/m²
The rms value of the electric field is given by;
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Answer:
Explanation:
A 6.0-cm-diameter parallel-plate capacitor has a 0.46 mm gap.
What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?
Let given is,
The diameter of a parallel plate capacitor is 6 cm or 0.06 m
Separation between plates, d = 0.046 mm
The potential difference across the capacitor is increasing at 500,000 V/s
We need to find the displacement current in the capacitor. Capacitance for parallel plate capacitor is given by :
, r is radius
Let I is the displacement current. It is given by :
Here, is rate of increasing potential difference
So
So, the value of displacement current is .