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Answer:
Explanation:
You can convert the <em>density</em> into <em>atomic density</em> using the <em>atomic weight </em>and Avogadro's number
A dimensional analysis is very helpful:
Follow the chain: g cancels with g, mol cancels with mol; at the end, what remains is atoms/cm³, which is what you want.
Use that with your data:
The experimental method for measuring the change in concentration with time for the given reaction is by measuring the amount of gas a reaction releases over time.
2NO(g) + Cl₂(g) → 2NOCl(g)
<h3>What is reaction rate?</h3>
- The reaction rate is the rate at which a chemical reaction proceeds.
- Which is proportional to both the increase in a product's concentration per unit time and the decrease in a reactant's concentration per unit time.
- There is a wide range in reaction times.
- The general definition is that the term "rate of a reaction" refers to the pace at which a reaction occurs.
- As an illustration, iron rusting has a low reaction rate since the process is slow but wood burning has a high reaction rate because the process is quick.
Learn more about reaction rate here:
brainly.com/question/13440548
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Answer:
1.09 grams
Explanation:
According to the following chemical equation:
HF + NaNO₃ -> HNO₃ + NaF
1 mol of hydrogen fluoride (HF) produces 1 mol of sodium fluoride (NaF). Thus, we first convert from mol to grams by using the molar mass (MM) of each compound:
MM(HF)= (1 g/mol x 1 H) + (19 g/mol x 1 F) = 20 g/mol HF
1 mol HF x 19.9 g/mol HF = 20 g
MM(NaF) = (23 g/mol x 1 Na) + (19 g/mol x 1 F) = 42 g/mol NaF
1 mol NaF x 42 g/mol NaF = 42 g
Thus, from 20 g of HF are produced 42 g of NaF ⇒ 20 g HF/42 g NaF. We multiply this stoichiometric ratio by the mass of NaF produced to calculate the required mass of HF:
20 g HF/42 g NaF x 2.3 g NaF = 1.09 g HF
Therefore, 1.09 grams of HF are necessary to produce 2.3 g of NaF.
<span>Should be 3.2*10^-2 moles</span>
