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tiny-mole [99]
3 years ago
5

25 PTs

Physics
1 answer:
Nuetrik [128]3 years ago
8 0
Answer:
They are both wrong!

Liquid oxygen really is a pale blue color.
I’ve seen it.

And they cant say that liquid and solid oxygen is blue which makes the sky blue because they’re not and it doesn’t make up for the color of the sky.

The sky is actually blue because It reflects more light than It can absorb
aka Rayleigh Scattering.

-HOPE THAT HELPED
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A student connects four AA batteries (1.5 V each) in series to light up a light bulb. The circuit has a resistance of 50 Ω. How
VLD [36.1K]

Answer:

0.3

Explanation:

V = I R

1.5= I (50)

I = 1.5/50

I = 0.3 J

Therefore, 0.3joule current flows through the circuit.

Hope this helped

5 0
3 years ago
Read 2 more answers
Which process is used to make low cost energy by nuclear power plant​
Anika [276]

Fission is used to make the low cost energy

7 0
3 years ago
A ball thrown vertically upward is caught by the thrower after 2.00 s. Find (a) the initial velocity of the ball and (b) the max
ankoles [38]

Answer:

a)  9.8 m/s

b) 4.9 m

Explanation:

This problem is a good example of Vertical motion, where the main equations for this situation are:  

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)  

V^{2}={V_{o}}^{2}-2gy (2)  

Where:  

y is the height of the ball at a given time

y_{o}=0m is the initial height of the ball (assuming the hand of the thrower the origin of the system)  

V_{o} is the initial velocity of the ball

V is the final velocity of the ball

t=2s is the time it takes for the ball to make the complete movement (from the moment it is thrown until it falls back into the pitcher's hands)

g=9.8 m/s^{2} is the acceleration due to gravity  

Knowing this, let's begin with the answers:

<h3>a) Initial velocity </h3>

In order to find the initial velocity V_{o} of the ball, we will use equation (1) and t=2s, taking into account that y=0 m and y_{o}=0m at this given time:

0=0+V_{o}t-\frac{1}{2}gt^{2} (3)  

Isolating V_{o}:

V_{o}=\frac{1}{2}gt (4)  

V_{o}=\frac{1}{2}(9.8 m/s^{2})(2 s) (5)  

Then:

V_{o}=9.8 m/s (6)  

<h3>b) Maximum height </h3>

In this part, we will use equation (2), knowing the value of the height is maximum when V=0. So, we will name this height as y_{max}:

0={V_{o}}^{2}-2gy_{max} (7)  

Isolating y_{max}:

y_{max}=\frac{{V_{o}}^{2}}{2g} (8)  

y_{max}=\frac{{(9.8 m/s)}^{2}}{2(9.8 m/s^{2})} (9)  

Finally:

y_{max}=4.9 m

4 0
3 years ago
!!PLEASE ANSWER ASAP!!
galina1969 [7]

A. elastic motion because that's the answer


8 0
3 years ago
Read 2 more answers
A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I
vodka [1.7K]

Answer:

a = 603.59 m/s^2

Explanation:

from the data given . the rate of change in magnetic field is as follow

\frac{dB}{dt} = 280 G/s = 280 \times 10^{-4} T/s

from the faraday's law of induction , the expression for the induced emf in region of radius r as follow

\epsilon = \frac{d \phi}{dt}

\int E.dl = \frac{d(BA)}{dt}

E(2\pi r)= \pi r^2 \frac{dB}{dt}

E = \frac{r}{2} \frac{dB}{dt}

electric field at point P_1 as follow

E = \frac{r}{2} \frac{dB}{dt}

E = \frac{1.5\times 10^{-2}}{2} 280 \times 10^{-4}

E = 6.3\times 10^{-6} V/m

from newton 2nd law of motion, the acceleration of proton is

F = ma

qE = ma

a = \frac{qE}{m}

a = \frac{1.6 \times 10^{-19} (6.3\times 10^{-6})}{1.67\times 10^{-27}}

a = 603.59 m/s^2

5 0
3 years ago
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