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Margaret [11]
3 years ago
12

There is a difference in color between the reactants and the product. Also, a gas and a solid bread loaf were produced, compared

to the liquid or powder forms of the reactants.
A. Color
B. Size
C. Shape
D. Volume
Chemistry
2 answers:
coldgirl [10]3 years ago
5 0
D. Volume
Yes hope this help!
vekshin13 years ago
3 0

heya buddy!!

d.volume

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Substance A has the following properties.
ella [17]

It will take 1.11 min to heat the sample to its melting point.

Melting point = - 20°C

Boiling point = 85°C

∆H of fusion = 180 J/g

∆H of vap = 500 J/g

C(solid) = 1.0 J/g °C

C(liquid) = 2.5 J/g °C

C(gas) = 0.5 J/g °C

Mass of sample = 25 g

Initial temperature = - 40°C

Final temperature = 100°C

Rate of heating = 450 J/min

Specific heat capacity formula:- q = m ×C×∆T

Here, q = heat energy

        m = mass

        C = specific heat

      ∆T = temperature change

Melting point = - 20°C

C(solid) = 1.0 J/g °C

∆T = final temperature - initial temperature = -20 - (-40) = 20

Put these value in  Specific heat capacity formula

q = m ×C×∆T

q = 25×1.0×20

   =500J

The Rate of heating = 450 J/min

i.e. 450J = 1min

so, 500J = 1.11min

1.11 minutes does it take to heat the sample to its melting point.

The specific heat capacity is defined as the amount of heat absorbed in line with unit mass of the material whilst its temperature increases 1 °C.

Learn more about specific heat capacity here:- brainly.com/question/26866234

#SPJ4

3 0
1 year ago
If 200 ml of 0.15 M propionic acid (PA) is added to 300 ml of 0.02 M NaOH, what is the resulting pH of the solution? Round the a
vodomira [7]

Answer:

pH = 4.543

Explanation:

  • CH3CH2COOH  + H2O ↔ CH3CH2COO-  +  H3O+
  • pKa = - Log Ka

∴ Ka = [H3O+][CH3CH2COO-]/[CH3CH2COOH]

∴ pKa = 4.87

⇒ Ka = 1.349 E-5 = [H3O+][CH3CH2COO-]/[CH3CH2COOH]

added 300 mL 0f 0.02 M NaOH:

⇒ <em>C</em> CH3CH2COOH = ((0.200 L)(0.15 M)) - ((0.300 L)(0.02 M))/(0.3 + 0.2)

⇒ <em>C</em> CH3CH2COOH = 0.048 M

⇒ <em>C</em> NaOH = (0.300 L)(0.02 M) / (0.3 +0.2) = 0.012 M

mass balance:

⇒ 0.048 + 0.012 = 0.06 M = [CH3CH2COO-] + [CH3CH2COOH].......(1)

charge balance:

⇒ [H3O+] + [Na+] = [CH3CH2COO-]

∴ [Na+] = 0.02 M

⇒ [CH3CH2COO-] = [H3O+] + 0.02 M.............(2)

(2) in (1):

⇒ [CH3CH2COOH] = 0.06 M - 0.02 M - [H3O+] = 0.04 M - [H3O+]

replacing in Ka:

⇒ 1.349 E-5 = [H3O+][([H3O+] + 0.02) / (0.04 - [H3O+])

⇒ (1.349 E-5)(0.04 - [H3O+]) = [H3O+]² + 0.02[H3O+]

⇒ 5.396 E-7 - 1.349 E-5[H3O+] = [H3O+]² + 0.02[H3O+]

⇒ [H3O+]² + 0.02001[H3O+] - 5.396 E-7 = 0

⇒ [H3O+ ] = 2.867 E-5 M

∴ pH = - Log [H3O+]

⇒ pH = 4.543

3 0
3 years ago
What do cyanobacteria use to produce energy and by what process do they produce energy
andrezito [222]
As they contain, green pigement they can perform "Photosynthesis" and obtains energy from that process

Hope this helps!
7 0
3 years ago
Can someone please help me please?
OleMash [197]
I would say the second option

Hope this helps *smiles*
8 0
3 years ago
• Compare non-transition and transition
Lyrx [107]

Answer:

nitrgen atom

Explanation:

periodic table

6 0
3 years ago
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