A charged particle moving in a magnetic field experiences a force equal to:

Thus, the magnitude of the force that the proton experiences is given by:

The magnetic field is perpendicular to the proton's velocity, therefore, we have
. Replacing the given values, we obtain:

That's ONLY true when the pendulum is hanging
in the center position and not moving.
Answer:
The magnitude of the average angular acceleration of the disk is
.
Explanation:
Given that,
Angular velocity, 
The disk comes to rest, 
Time, t = 0.234 s
We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,

So, the magnitude of the average angular acceleration of the disk is
.