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Ronch [10]
3 years ago
5

In which city rusting is a problem delhi or mumbai

Physics
1 answer:
ss7ja [257]3 years ago
3 0

Answer:

Mumbai

Explanation:

Because Mumbai is a coastal city

due to high humidity,vigorous rusting damages all the iron structures

∴ rusting is a major problem in Mumbai

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In a machine, work output is less than work input because some energy is converted into thermal energy. true or false.
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True ..........................
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The relationship between frequency wavelength and speed holds for light waves because
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Answer:

all forms of electromagnetic radiation travel at a single speed in a vacuum.

Explanation:

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3 years ago
A baseball is batted from a height of 1.09 m with a speed of
kobusy [5.1K]

(a) The horizontal and vertical components of the ball’s initial velocity is 37.8 m/s and 12.14 m/s respectively.

(b) The maximum height above the ground reached by the ball is 8.6 m.

(c) The distance off course the ball would be carried is 0.38 m.

(d) The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

<h3>Horizontal and vertical components of the ball's velocity</h3>

Vx = Vcosθ

Vx = 39.7 x cos(17.8)

Vx = 37.8 m/s

Vy = Vsin(θ)

Vy = 39.7 x sin(17.8)

Vy = 12.14 m/s

<h3>Maximum height reached by the ball</h3>

H = \frac{v^2 sin^2(\theta)}{2g} \\\\H = \frac{(39.7)^2 \times (sin17.8)^2}{2(9.8)} \\\\H = 7.51 \ m

Maximum height above ground = 7.51 + 1.09 = 8.6 m

<h3>Distance off course after 2 second </h3>

Upward speed of the ball after 2 seconds, V = V₀y - gt

Vy = 12.14 - (2x 9.8)

Vy = - 7.46 m/s

Horizontal velocity will be constant = 37.8 m/s

Resultant speed of the ball after 2 seconds = √(Vy² + Vx²)

V = \sqrt{(-7.46)^2 + (37.8)^2} \\\\V = 38.53 \ m/s

<h3>Resultant speed of the ball and crosswind</h3>

V = \sqrt{38.52^2 + 4^2} \\\\V = 38.72 \ m/s

<h3>Distance off course the ball would be carried</h3>

d = Δvt = (38.72 - 38.53) x 2

d = 0.38 m

The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.

Learn more about projectiles here: brainly.com/question/11049671

5 0
1 year ago
Two students are sitting 1.50 m apart. One student has a mass of 70.0 kg and
Galina-37 [17]

Answer:

1.08x10⁻⁷

Explanation:

F=(GM₁M₂)/r²

=((6.67x10⁻¹¹)(70)(52))/(1.5²)

=2.42788x10⁻⁷/2.25

=1.07905778x10⁻⁷

≈1.08x10⁻⁷

3 0
3 years ago
Will a solid metal sphere hold a larger elaectric charge than a hollow sphere of the same diameter?Where does the charge reside
melomori [17]
The answer would be no. Both will have same charge, in both caes charge will reside on surface. In case of solid sphere it will be distributed evenly throughout. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
4 0
3 years ago
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