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KatRina [158]
3 years ago
6

Answer the question below pls

Chemistry
2 answers:
Veseljchak [2.6K]3 years ago
6 0

Answer:

The answer would be at 120°C

Archy [21]3 years ago
5 0
120 degrees Celsius
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The reduction of aldehydes, ketones, organic acids and their derivative of the process of alcohols is used for
ikadub [295]

Answer:

Widening of blood vessels.

Explanation:

The reduction of aldehydes, ketones, organic acids causes the formation of alcohols that is used for different process in the human body. This alcohol increase the width of the blood vessels as it enters the bloodstream causing greater flow of blood to the skin surface as well as temporary feeling of warmth. It also increased heat loss and rapid body temperature decrease that produces cooling effect in the body.

8 0
3 years ago
How many atomic orbitals of each type mix to form hybrid orbitals of the central atom in cl2o?
lidiya [134]

In here Oxygen is the central atom. It makes two bonds with Cl and has two lone pairs. Since, the shape is bent and the hybridization is sp3. Molecular geometry is a bit dissimilar from hybridization. Hybridization is reliant on the number of bonds and lone pairs. Since O has two bonds with Cl, its hybridization is sp3. It is like is this: 1 lone pair/bond = s. 2 lone pairs/bond = sp 3 lone pairs/bonds = sp2, etc. molecular geometry, you count the number of bonds and lone pairs. This has two bonds and 2 lone pairs so if they were all bonds, the molecule would be tetrahedral. 

4 0
4 years ago
Read 2 more answers
What’s a conjugative Bas of OH-
LiRa [457]

Answer:

the answer is O²- hopefully

8 0
3 years ago
Compounds both and mixtures
zavuch27 [327]
Compounds=Chemically combined, fixed proportions,and components change properties.
Both= Made of elements, and 2 or more components.
Mixtures=Physically combined, variable proportions, and components retain properties.
6 0
3 years ago
Watch the animation and observe the titration process of a standard 0.100 M sodium hydroxide solution with 50.0 \rm ml of a 0.10
yuradex [85]

Answer:

Answers are in the explanation

Explanation:

a. The statments are:

The titration process is based on a chemical reaction.  <em>TRUE. </em>A titration is the chemical reaction between an acid and a base.

The pH of the solution at the equivalence point is 7.  <em>TRUE. </em>In a titration of strong acid with strong base the equivalence point is 7

At the endpoint, the pH of solution is 10 and the color of solution is pink.  <em>FALSE</em>. The endpoint in a strong acid - strong base titrationmust be near to equivalence point at pH = 7.

At the beginning of the titration process, the pH of the solution increases rapidly.  <em>FALSE. </em>At beginning of a titration, the pH of the solution increases slowly.

The chemical reaction involved in an acid-base titration is a neutralization reaction.  <em>TRUE. </em>In the reaction, you are neutralizing an acid (HCl) with a base (NaOH)

Before any base is added to the solution, the pH of the solution is high. <em>FALSE. </em>The addition of a base increases pH that is, in the beginning, low.

In a titration process, the endpoint is reached before the equivalence point.  <em>FALSE. </em>In a titration process, the endpoint is reached in the equivalence point

The pH of the solution changes very slowly at the equivalence point. <em>FALSE. </em>At the equivalence point, the pH changes rapidly.

b. For the reaction

NaOH + HCl → H₂O + NaCl

As the reaction is 1:1 and molarity of both solutions are the same, additions < 100mL of NaOH will stay before the equivalence point, equivalence point will be in 100mL and additions > 100mL of NaOH will stay after the equivalence point.

The conditions are:

10.0mL of 1.00 M NaOH before the equivalence point

150 mL of 1.00 M NaOH after the equivalence point

5.00 mL of 1.00 M NaOH before the equivalence point

50.0 mL of 1.00 M NaOH  before the equivalence point

200 mL of 1.00 M NaOH after the equivalence point

I hope it helps!

7 0
3 years ago
Read 2 more answers
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