PH is your answer
Hope this helps!!
I'm not going toblie I'm stuck with A and B.
But to me my gut says A
The molar mass of methylammonium bromide is 111u.
<h3>What is molar mass?</h3>
The molar mass is defined as the mass per unit amount of substance of a given chemical entity.
Multiply the atomic weight (from the periodic table) of each element by the number of atoms of that element present in the compound.
Add it all together and put units of grams/mole after the number.
Atomic weight of H is 1u
Atomic weight of N is 14u
Atomic weight of C is 12u
Atomic weight of Br is 79u
Calculating molar mass of
=2(1 x3+ 14+12+ 1 x 3 +79) = 111u
Hence, the molar mass of methylammonium bromide is 111u.
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Answer:
Molarity of
solution is 0.612 mol/L
Explanation:
Number of moles of a substance = (mass of substance)/(molar mass of the substance)
Molar mass of
= 214 g/mol
So, 562 g of
=
moles of
= 2.63 moles of 
Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)
Here solute is
and solvent is water
Total volume of solution is 4.30 L
So, molarity of
solution =
= 0.612 mol/L
The solution 550 ml total and first we will find the amount of alcohol. 3% = 0.03 550 ml x .03 = 16.5 ml alcohol
Then to find the amount of water used, we just have to subtract the amount of alcohol from the total volume
550 ml total - 16.5 ml alcohol = 533.5 ml water