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3 years ago

What is the molarity of 392 mL of solution that contains 0.47 mol NaCl?

Chemistry

1 answer:

jek_recluse [69]3 years ago

5 0

Answer: 1.2 M

Explanation:

Given that:

volume of NaCl = 392 mL

Convert volume in milliliters to liters

(since 1000 mL = 1L

392 mL = 392/10000 = 0.392 L)

Concentration of NaCl = ?

Amount of moles of NaCl = 0.47 moles

Recall that the concentration of a solution depends on the amount of solute dissolved in a particular volume of solvent.

I.e Concentration in mol/L =

Amount in moles / Volume in liters

= 0.47 moles / 0.392 L

= 1.199 mol/L (Round up to the nearest tenth as 1.2 M)

Note that molarity is the same as concentration in moles per litres.

Thus, the molarity of 392 mL of solution that contains 0.47 mol NaCl is 1.2 M

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A strontium hydroxide solution is prepared by dissolving 10.60 gg of Sr(OH)2Sr(OH)2 in water to make 47.00 mLmL of solution.What

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Note that both figures in the question come with four significant figures. Therefore, the answer should also be rounded to four significant figures. Intermediate results should have more significant figures than that.

<h3>Formula mass of strontium hydroxide</h3>

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$M\left(\rm Sr(OH)_2\right) =121.634\; \rm g \cdot mol^{-1}$ means that each mole of $\rm Sr(OH)_2$ formula units have a mass of $121.634\; \rm g$ .

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How many moles of $\rm Sr(OH)_2$ formula units would that be?

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<h3>Molarity of this strontium hydroxide solution</h3>

There are $8.71467\times 10^{-2}\; \rm mol$ of $\rm Sr(OH)_2$ formula units in this $47\; \rm mL$ solution. Convert the unit of volume to liter:

$V = 47\; \rm mL = 0.047\; \rm L$ .

The molarity of a solution measures its molar concentration. For this solution:

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(Rounded to four significant figures.)

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