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3 years ago

Witch element(s) are not balanced\ in this equation?:fe2o3 + 3co → fe + 3co2 plz answer :3

Chemistry

1 answer:

Lostsunrise [7]3 years ago

3 0

Fe and o
it should be 2fe2o3 + 6co -> 2fe2 + 6co2
I think. I am not sure

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3 years ago

A technician needs 500.0mL of a 0.500 M MgCl2 solution for some lab procedures. The stock bottle is labeled 4.00 M MgCl2. What v

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Answer:

Explanation:

To solve this problem, we need to obtain the number of moles of the solute we desired to prepare;

Number of moles = molarity x volume

Parameters given;

volume of solution = 500mL = 0.5L

molarity of solution = 0.5M

Number of moles = 0.5 x 0.5 = 0.25moles

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3 years ago

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D. They all contain carbon as an important part of their structure.

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denis-greek [22]

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6 0

3 years ago

(a) Show that the pressure exerted by a fluid P (in pascals) is given by P = hdg, where h is the column of the fluid in metres,

Komok [63]

Answer:

B) THE DEPTH OF THE LAKE IS 0.060 m

Explanation:

b) Determine the depth of the lake in metres

1. Using the general gas law, we will calculate the initial pressure of the air bubbles.

P1V1 /T1 = P2V2/T2

P1 = Unknown

T1 = 5.24 °C

T2 = 18.73 °C

P2 = 0.973 atm

V1 = V1

V2 = 6V1

P1 = P2 V2 T1 / V1 T2

P1 = 0.973 * 6V1 * 5.24 / V1 * 18.73

P1 = 5.09852 * 6 / 18.73

P1 = 30.59112 / 18.73

P1 = 1.633 atm.

2. Calculate the depth of the lake:

Pressure = length * density * acceleration

length = Pressure / density * acceleration

Pressure = 1.633 atm = 1.633 * 101, 325 Nm^2 = 165, 463.725 Nm^2

Density = 1.02 g/cm3 = 1.02 * 10^3 kg/m^3

Acceleration = 9.8 m/s^2

So therefore, the length in metres is:

Length = density * acceleration / pressure

Length = 1.02 *10^3 * 9.8 / 165, 463.725

Length = 9.996 * 10^3 / 165 463.725

Length = 0.06 m

Hence, the depth of the lake is 0.06 m

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3 years ago