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3 years ago

Witch element(s) are not balanced\ in this equation?:fe2o3 + 3co → fe + 3co2 plz answer :3

Chemistry

1 answer:

Lostsunrise [7]3 years ago

3 0

Fe and o
it should be 2fe2o3 + 6co -> 2fe2 + 6co2
I think. I am not sure

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3 years ago

In 0.4 mole of H2S, how many atoms of H are there?

Debora [2.8K]

Answer:

Explain

H: Ignoring the coefficient, we know there's 5+3=8 atoms

5 0

2 years ago

5) How many moles are in 5 Liters of H2 gas?

telo118 [61]

From 5 L to moles, just divide 5 by 22.4. I got 0.22 moles of H2.
From 5 moles to liters, just multiply 5 by 22.4. I got 112 L of H2.

4 0

3 years ago

This is my chemistry worksheet. It's a new topic my teacher will barely review with us. Help please???

TEA [102]

So to balance an equation, you need to get the same amount of each type of element on either side of the --> . So you pretty much are given the subscripts in the equations and you need to add coefficients (just normal numbers) in front of any formula that needs it, keeping anything balance.
$KCl_{3} + O_{2} -\ \textgreater \ KCl_{3}$
turns into
$2KCl_{3}+ 3O_{2} -> 2KCl_{3}$

These coefficient numbers are the molar ratios, so 2 moles of KCl3 for every 3 moles of O2 so 1. 3:2

Then you can use these ratios of find out how many moles of one thing are needed if you are given the amount of another.
$\frac{moles of element 1}{cofficient 1} = \frac{moles of element 2}{cofficient 2}$
and use cross multiplication to solve for whatever you don't know

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6 0

3 years ago

PLEASE HELP ASAP!

choli [55]

Answer:

$\large \boxed{\text{D. 710 g}}$

Explanation:

1. Calculate the molar mass of Na₂SO₄

$\begin{array}{ccc}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 23 & 46\\\text{1S} & 32 & 32\\\text{4O}&16 & 64\\&\text{TOTAL =} & \mathbf{142}\\\end{array}$

The molar mass of Na₂SO₄ is 142 g/mol.

2. Calculate the moles of Na₂SO₄

$\text{Moles of Na$_{2}$SO}_{4} = \text{2.5 L solution} \times \dfrac{\text{2.0 mol Na$_{2}$SO}_{4}}{\text{1 L solution}} = \text{5.0 mol Na$_{2}$SO}_{4}$

3. Calculate the mass of Na₂SO₄

$\text{Mass of Na$_{2}$SO}_{4} = \text{5.0 mol Na$_{2}$SO}_{4} \times \dfrac{\text{142 g Na$_{2}$SO}_{4}}{\text{1 mol Na$_{2}$SO}_{4}} = \text{710 g Na$_{2}$SO}_{4}\\\\\text{You need } \large \boxed{\textbf{710 g}} \text{ of Na$_{2}$SO}_{4}$

6 0

3 years ago