Answer is: molarity of solution is 0,5 mol/dm³.
m(NaOH) = 10,0 g.
V(NaOH) = 500 ml = 0,5 dm³.
c(NaOH) = ?
n(NaOH) = m(NaOH) ÷ M(NaOH).
n(NaOH) = 10,0 g ÷ 40 g/mol.
n(NaOH) = 0,25 mol.
c(NaOH) = n(NaOH) ÷ V(NaOH).
c(NaOH) = 0,25 mol ÷ 0,5 dm³.
c(NaOH) = 0,5 mol/dm³.
The empirical formula : C₆H₂Cl₂O
The molecular formula : C₁₂H₄Cl₄O₂
<h3>Further explanation</h3>
Given
The percentage composition
Required
The empirical formula and the molecular formula
Solution
The mol ratio of the components :
C : H : Cl : O
=44.76/12 : 1.25/1 : 44.05/35.5 : 9.94/16
=3.73 : 1.25 : 1.241 : 0.621 divide by 1.241
= 3 : 1 : : 1 : 0.5 x 2
= 6 : 2 : 2 : 1
The empirical formula : C₆H₂Cl₂O
(Empirical formula)n=molecular formula
(C₆H₂Cl₂O)n=321.97
(160.986)n=321.97
n=2
(C₆H₂Cl₂O)₂=C₁₂H₄Cl₄O₂
The molecular formula : C₁₂H₄Cl₄O₂
Answer:
The systematic naming of chemicals is the IUPAC name (International Union of Pure and Applied Chemistry).
Here are the purposes to use it:
1/ It identifies exactly one chemical.
2/ All people over the world can understand it, wherever they are, whoever they are.
It looks like how we recognise the number 1 - 2 - 3: the Americans call them One Two Three, but the Russian call them Odin Dva Tri, etc....
Explanation:
Hope this answer can help you!
Answer: 3.4 L
Explanation:
To calculate the moles, we use the equation:
The balanced chemical equation for reaction of Hydrogen chloride gas with oxygen to form water vapor and chlorine gas.
According to stoichiometry :
4 moles of 
produce = 2 moles of 
Thus 0.29 moles of will produce =
of
Volume of 
Thus 3.4 L of of water would be produced by this reaction if 6.5 L of hydrogen chloride were consumed
