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lawyer [7]
4 years ago
12

What is a molecular dipole moment?

Chemistry
1 answer:
k0ka [10]4 years ago
8 0
B. is the right option. hope it will help you!
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Calcium is a nontoxic metal that is used in supplements to maintain strong bones. Under high pressure conditions, over about 320
Lera25 [3.4K]

Explanation:

It is known that in a simple cubic unit cell the atoms are only present at the corner of the unit cell. This means that there are in total 8 atoms present in a simple cubic unit cell.

Therefore, in one simple cubic unit cell sharing of one atom is only \frac{1}{8}.

Hence, the total number of atoms in a unit cell will be as follows.

            8 \times \frac{1}{8} = 1

Thus, we can conclude that there is 1 calcium atom present in each unit cell.

4 0
3 years ago
The solubility of glucose at 30°C is
weqwewe [10]

Answer:

Saturated solution

We should raise the temperature to increase the amount of glucose in the solution without adding more glucose.

Explanation:

Step 1: Calculate the mass of water

The density of water at 30°C is 0.996 g/mL. We use this data to calculate the mass corresponding to 400 mL.

400 mL \times \frac{0.996g}{1mL} =398g

Step 2: Calculate the mass of glucose per 100 g of water

550 g of glucose were added to 398 g of water. Let's calculate the mass of glucose per 100 g of water.

100gH_2O \times \frac{550gGlucose}{398gH_2O} = 138 gGlucose

Step 3: Classify the solution

The solubility represents the maximum amount of solute that can be dissolved per 100 g of water. Since the solubility of glucose is 125 g Glucose/100 g of water and we attempt to dissolve 138 g of Glucose/100 g of water, some of the Glucose will not be dissolved. The solution will have the maximum amount of solute possible so it would be saturated. We could increase the amount of glucose in the solution by raising the temperature to increase the solubility of glucose in water.

6 0
3 years ago
URGENT!! Can someone please explain this to me?
djverab [1.8K]

Answer:

CH _{4}+ 2O  _{2} → CO _{2} + 2H _{2}O

for the balanced equation

from \: the \: equation \\ 1 \: mole \: of \: methane \: gives \: 1 \: mole \: of \: carbon \: dioxide \\ 7.4 \: moles \: of \: carbon \: dioxide \: will \: be \: given \: by \: (7.4 \times 1)moles \: of \: methane \\  = 7.4\: moles \: of \: methane \\  \\  since \: moles \: of \: oxygen \: double \: those \: of \: methane \\ moles \: of \: oxygen \:  = 7.4\times 2 \\  = 14.8 \: moles \: of \: oxygen

4 0
3 years ago
An aqueous solution contains 32.7% KCl (wt/wt%). what is the mole fraction of KCl in the solution
inna [77]

The mole fraction of KCl in the solution is 0.1051

calculation

mole fraction of KCl in solution = moles of KCl / total number of moles(moles of KCl +moles of H2O)

moles=mass/molar mass

mass of KCl=32.7g

molar mass of KCl= 39 +35.5

moles of KCl is therefore= 32.7g/74.5 g/mol=0.439 moles

find the moles of H2O= mass of H2O/molar mass

mass of H2O=100-32.7=67.3g

molar mass of H2O=( 1 x2) +16=18 g/mol

moles = 67.3/18 =3.739 moles

total moles=3.739+0.439=4.178 moles

mole fraction is therefore=0.439/4.178=0.1051

5 0
3 years ago
Naphthalene combustion may be used to calibrate the heat capacity of a bomb calorimeter. The heat of combustion of naphthalene i
tino4ka555 [31]

Answer:

.

Explanation:

5 0
3 years ago
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