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frutty [35]
3 years ago
13

The molar mass of a gas is 56 grams. What is its density at STP in grams per liter?

Chemistry
1 answer:
ivolga24 [154]3 years ago
7 0

Answer:

d = 2.5 g/L

Explanation:

Given data:

Molar mass of gas = 56 g/mol

Density of gas = ?

Temperature = 273.15 K

Pressure = 1 atm

Solution:

Formula:

d = PM/RT

d = 1 atm × 56 g/mol / 0.0821 atm.L/mol.K ×273.15 K

d = 56 atm  g/mol./ 22.42 atm.L/mol

d = 2.5 g/L

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If an atom of an element has a mass number of 45 and it has 20 neutrons in its nucleus, what is the atomic number of the
HACTEHA [7]

Answer:

Explanation:

uestion

If an atom of an element has a mass number of 45 and it has 20 neutrons in its nucleus, what is the atomic number of the

element?

3 0
3 years ago
Carbon-12 contains 6 protons and 6 neutrons. The radius of the nucleus is approximately 2.7 fm (femtometers) and the radius of t
Slav-nsk [51]

Explanation:

Let us assume that volumes is equal to spheres  volume of nucleus.

fm = femto meter = 10^{-15}

pm = pico meter = 10^{-12}

Hence, calculate the volume as follows.

          V = \frac{4}{3} \times \pi \times r^{3}

              = \frac{4}{3} \times 3.14 \times (2.7)^{3}

              = 82.4481 fm^{3} (cubic femtometers)

or,          = 82 fm^{3}

Now, we will calculate the volume of the atom as follows.

          V = \frac{4}{3} \times \pi \times r^{3}

             = \frac{4}{3} \times 3.14 \times (70)^{3}

             = 1436758.4 pm^{3} (cubic picometers)

thus, we can conclude that volume of the nucleus is 82 fm^{3}  and volume of the atom is 1436758.4 pm^{3}.

7 0
3 years ago
If the mixing ratio of a parcel of air is 6 grams per kilogram and the relative humidity is 25 percent, the saturation mixing ra
Y_Kistochka [10]

Answer: -

24 grams per kilogram.

Explanation: -

We know that

The mixing ratio = actual (measured) mass of water vapor (in parcel) in grams / mass of dry (non water vapor) air (in parcel) in kilogram

The saturation mixing ratio = mass of water vapor required for saturation (in parcel) in grams/ mass of dry (non water vapor) air (in parcel) in kilograms

Relative humidity = actual (measured) water vapor content/ maximum possible water vapor amount (saturation)

Thus saturation mixing ratio = Mixing ratio / relative humidity

= 6 / (25/100)

= 24

4 0
3 years ago
What volume of oxygen gas is released at STP if 10.0 g of potassium chlorate is decomposed? (The molar mass of KClO3 is 122.55 g
ArbitrLikvidat [17]
<span>KCl<span>O3</span><span>(s)</span>+Δ→KCl<span>(s)</span>+<span>32</span><span>O2</span><span>(g)</span></span>

Approx. <span>3L</span> of dioxygen gas will be evolved.

Explanation:

We assume that the reaction as written proceeds quantitatively.

Moles of <span>KCl<span>O3</span><span>(s)</span></span> = <span><span>10.0⋅g</span><span>122.55⋅g⋅mo<span>l<span>−1</span></span></span></span> = <span>0.0816⋅mol</span>

And thus <span><span>32</span>×0.0816⋅mol</span> dioxygen are produced, i.e. <span>0.122⋅mol</span>.

At STP, an Ideal Gas occupies a volume of <span>22.4⋅L⋅mo<span>l<span>−1</span></span></span>.

And thus, volume of gas produced = <span>22.4⋅L⋅mo<span>l<span>−1</span></span>×0.0816⋅mol≅3L</span>

Note that this reaction would not work well without catalysis, typically <span>Mn<span>O2</span></span>.


8 0
3 years ago
Read 2 more answers
The pressure of a sample of helium in a 200. ml. container is 2.0 atm. If the 5 points
just olya [345]

The pressure of the gas = 40 atm

<h3>Further explanation</h3>

Given

200 ml container

P = 2 atm

final volume = 10 ml

Required

Final pressure

Solution

Boyle's Law  

At a fixed temperature, the gas volume is inversely proportional to the pressure applied  

\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

Input the value :

P₂ = P₁V₁/V₂

P₂ = 2 x 200 / 10

P₂ = 40 atm

3 0
3 years ago
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