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2 years ago

What is the mass of 2.486 * 10^{24} atoms of neon?

Chemistry

1 answer:

lorasvet [3.4K]2 years ago

4 0

Answer:

The answer is A 83.33 g Ne

Explanation:

Used Avogadros Law

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HELP ITS IN TBE PICTURE

Art [367]

Physical change. you are physically altering it, not chemically

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3 years ago

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PLEASE HELP

charle [14.2K]

Answer: The statement, average kinetic energy of the gas particles is greater in container A because its particles move faster is correct.

Explanation:

Kinetic energy is the energy obtained due to the motion of an object or substance.

$K.E = \frac{3}{2}kT$

where,

T = temperature

This means that kinetic energy is directly proportional to temperature.

So, when heat is provided to container A then its molecules will start to move rapidly from one place to another which will cause more collisions between the atoms.

Hence, average kinetic energy will be more in container A.

Whereas container B is placed at room temperature which is low than that in container A. So, molecules in container B will move at almost same speed and therefore, specific collisions will be there. So, average kinetic energy in container B will be less than that in container A.

Thus, we can conclude that the statement, average kinetic energy of the gas particles is greater in container A because its particles move faster is correct.

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2 years ago

What kind of energy can be transferred?<br><br> Help quick please.

defon

Answer:

Any kind, as long as there is an action.

7 0

3 years ago

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Suppose 215 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?

charle [14.2K]

Answer:

The answer is " $41.23 \ L\ N_2$ "

Explanation:

$2 NO_3^{-} + 10 e^{-} + 12 H^{+} \longrightarrow N_2 + 6 H_2O\\\\= \frac{( 215 \ g \ NO_3^{-})}{(62.0049 \frac{\ g NO_3^{-}}{mol})} \times \frac{(1 \ mol \ N_2}{ 2 \ mol \ NO_3^{-})}\\\\$

$=3.46746789 \times 0.5\\\\= 1.733 \ mol \ N_2 \\\\\to V = \frac{nRT}{P} \\\\= (1.733 \ mol) \times (0.08205746 \frac{L\ atm}{Kmol}) \times \frac{ (17 + 273) K}{(1.00 atm)}\\\\= 41.23$

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3 years ago

If 1.0 gram of hydrogen reacts with 19.0 grams of fluorine, then what is the percent by mass of fluorine in the compound that is

astraxan [27]

The reaction between hydrogen (H2) and fluorine (F2) is given below,
H2 + F2 ---> 2HF
One mole of both hydrogen and fluorine yields to 2 moles of hydrogen fluoride. This can also be expressed as, 2 grams of hydrogen and 38 grams of fluorine will form 40 grams of hydrogen fluoride. From the given, only 20 grams of HF is formed with 19 g of it being fluorine. Thus, the percentage fluorine of the compound formed is 95%.

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3 years ago

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