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4 years ago

Describe why a high-efficiency machine is more desirable than a low-efficiency machine.

1 answer:

6 0

A high efficiency machine take in less and puts out more. That's why efficient cars and computers have betters engines/processors and work faster. They eliminate unneeded drag in order to maximize speed.

Hope this helps, Brainliest please

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What is sound reverberation?

otez555 [7]

Sound reverberation is created when sound or signal is reflected.

3 0

3 years ago

A block of mass 3.20 kg is placed against a horizontal spring of constant k = 865 N/m and pushed so the spring compresses by 0.0

Aliun [14]

Answer:

a) The initial elastic potential energy of the block-spring system is 28.113 joules.

b) The final speed of the block is approximately 4.192 meters per second.

Explanation:

a) By applying Hooke's law and definition of work, we define the elastic potential energy ( $U_{g}$ ), measured in joules, by the following formula:

$U_{g} = \frac{1}{2}\cdot k\cdot x^{2}$ (1)

Where:

$k$ - Spring constant, measured in newtons per meter.

$x$ - Deformation of the spring, measured in meters.

If we know that $k = 865\,\frac{N}{m}$ and $x = 0.065\,m$ , then the elastic potential energy is:

$U_{g} = \frac{1}{2}\cdot \left(865\,\frac{N}{m} \right) \cdot (0.065\,m)$

$U_{g} = 28.113\,J$

The initial elastic potential energy of the block-spring system is 28.113 joules.

b) According to the Principle of Energy Conservation, the initial elastic potential energy of the block-spring system becomes into translational kinetic energy, that is:

$U_{g} = \frac{1}{2}\cdot m\cdot v^{2}$ (2)

Where:

$m$ - Mass, measured in kilograms.

$v$ - Final speed, measured in meters per second.

Then, the final speed is cleared:

$v = \sqrt{\frac{2\cdot U_{g}}{m} }$

If we know that $U_{g} = 28.113\,J$ and $m = 3.20\,kg$ , then the final speed of the block is:

$v = \sqrt{\frac{2\cdot (28.113\,J)}{3.20\,kg} }$

$v \approx 4.192\,\frac{m}{s}$

The final speed of the block is approximately 4.192 meters per second.

3 0

3 years ago

A 1.70 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1

Nikitich [7]

Resistance = ρ * (L/A) and Rf = Ri * ([1 + α * (Tf – Ti)]
ρ = Resistivity L = length in meters A = cross sectional area in m^2 α = temperature coefficient of resistivity
L = 1.50 m Area = π * r^2 r = d/2 = 0.25 cm = 2.5 * 10^-3 m Area = π * (2.5 * 10^-3)^2

The cylindrical rod is similar to a resistor. Since the current is decreasing, the resistance must be increasing. This means the resistance is increasing as the temperature increases. Resistance = Voltage ÷ Current At 20˚, R = 15 ÷ 18.5 At 92˚, R = 15 ÷ 17.2

Now you know the resistance at the two temperatures. Let’s determine the resistivity at the two temperatures. Resistance = ρ * (L/A) ρ = Resistance * (A/L)
At 20˚, ρ = (15 ÷ 18.5) * [π * (2.5 * 10^-3)^2] ÷ 1.5 = At 92˚, ρ = (15 ÷ 17.2) * [π * (2.5 * 10^-3)^2] ÷ 1.5 =
Now you know the resistivity at the two temperatures. Let’s determine the temperature coefficient of resistivity for the material of the rod.
Rf = Ri * ([1 + α * (Tf – Ti)] Rf = 15 ÷ 17.2, Ri = 15 ÷ 18.5, Tf = 92˚, Ti = 20˚
15 ÷ 17.2 = 15 ÷ 18.5 * [1 + α * (92 – 20)] Multiply both sides by (18.5 ÷ 15) (18.5 ÷ 15) * (15 ÷ 17.2) = 1 + α * 72 Subtract 1 from both sides (18.5 ÷ 15) * (15 ÷ 17.2) – 1 = α * 72 Divide both sides by 72 α = 1.05 * 10^-3

4 0

3 years ago

If atmospheric pressure suddenly changes from 1.00 atm to 0.896 atm at 298 k, how much oxygen will be released from 3.30 l of wa

xxMikexx [17]

At a temperature of 298 K, the Henry's law constant is 0.00130 M/atm for oxygen. The solubility of oxygen in water 1.00 atm would be calculated as follows:

S = (H) (Pgas) = 0.00130 M / atm x 0.21 atm = 0.000273 M

At 0.890 atm,
S = (H)(Pgas) = 0.00130 M / atm x 0.1869 atm = 0.00024297 M

If atmospheric pressure would suddenly change from 1.00 atm to 0.890 atm at the same temperature, the amount of oxygen that will be released from 3.30 L of water in an unsealed container would be as follows

3.30 L x (0.000273 mol / L) = 0.0012012 mol

3.30 L x (0.00024297 mol / L) = 0.001069068 mol

0.0012012 mol - 0.001069068 mol = 0.000132 mol

6 0

4 years ago

What is the public storm warning signal that carries winds of 30 to 60 km/hr and can cause no damage to very light damage

Shkiper50 [21]

Answer:

I know u need this

Explanation:

You gave me the runaround

I really hate the runaround

You really got me paranoid

I always keep a gun around

You always give me butterflies

When you come around

7 0

3 years ago