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vampirchik [111]
3 years ago
11

What is the wavelenght and the frequencen of walkie-talkie?

Physics
1 answer:
GuDViN [60]3 years ago
8 0
Nowadays, most of the walkie talkies ... and all R/C models ... operate in the "Family Radio Service" (FRS) band. That's 46-49 MHz. The wavelength is 6.12-6.52 meters.
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A key falls from a bridge that is 32 m above the water. It falls directly into a model boat, moving with constant velocity, that
FinnZ [79.3K]

Answer:

Speed of the boat, v = 4.31 m/s

Explanation:

Given that,

Height of the bridge, h = 32 m

The model boat is 11 m from the point of impact when the key was released, d = 11 m

Firstly, we will find the time needed for the boat to get in this position using second equation of motion as :

s=ut+\dfrac{1}{2}at^2

Here, u = 0 and a = g

t=\sqrt{\dfrac{2s}{g}}

t=\sqrt{\dfrac{2\times 32}{9.8}}

t = 2.55 seconds

Let v is the speed of the boat. It can be calculated as :

v=\dfrac{d}{t}

v=\dfrac{11\ m}{2.55\ s}

v = 4.31 m/s

So, the speed of the boat is 4.31 m/s. Hence, this is the required solution.

3 0
3 years ago
A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the wavelengt
azamat

bvcdbcvfdnbgfbjdgfhdgfjghfjhvjbczdfsghdfshjdgfhdftgh

8 0
3 years ago
A wooden cube with the mass of 1kg is placed on a frictionless plane that makes an angle of 30° with the floor.
Anni [7]

Answer:

I dont know

Explanation:

8 0
2 years ago
A large lightning bolt consists of a 18.2~\text{kA}18.2 kA current that moved 30.0~\text{C}30.0 C of charge. Assuming a constant
marissa [1.9K]

Answer:

1.65\times {-3} \text { s}

Explanation:

Current is the rate of flow of charge.

I=\dfrac{Q}{t}

t = \dfrac{Q}{I}

t = \dfrac{30.0}{18.2\times10^3} =1.65\times {0-3} = 1.65\times {-3} \text { s}

6 0
2 years ago
Read 2 more answers
Sapting Leng You have a string with a mass of 13.7 q. You stretch the string with a force of 8.39 N, giving it a length of 1.87
marshall27 [118]

Answer:

a)  \lambda=0.935\ \textup{m}

b) f=36.19\approx 36\ \textup{Hz}

Explanation:

Given:

String vibrates transversely fourth dynamic, thus n = 4

mass of the string, m = 13.7 g = 13.7 × 10⁻¹³ kg

Tension in the string, T = 8.39 N

Length of the string, L = 1.87 m

a) we know

L= n\frac{\lambda}{2}

where,

\lambda = wavelength

on substituting the values, we get

1.87= 4\times \frac{\lambda}{2}

or

\lambda=0.935\ \textup{m}

b) Speed of the wave (v) in the string is given as:

v =f\lambda

also,

v=\sqrt\frac{T}{(\frac{m}{L})}

equating both the formula for 'v' we get,

f\lambda=\sqrt\frac{T}{(\frac{m}{L})}

on substituting the values, we get

f\times 0.935=\sqrt\frac{8.39}{(\frac{13.7\times 10^{3}}{1.87})}

or

f=\frac{33.84}{0.935}

or

f=36.19\approx 36\ \textup{Hz}

5 0
2 years ago
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