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katrin2010 [14]
3 years ago
8

Consider the diagram for the following questions.

Physics
2 answers:
Slav-nsk [51]3 years ago
6 0

Answer:

charges

vectors

Explanation:

edg never lies

Ksivusya [100]3 years ago
4 0

Answer:

1) Charges

2) Vectors

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initially, a particle is moving at 5.33 m/s at an angle of 37.9° above the horizontal. Two seconds later, its velocity is 6.11 m
Ainat [17]

Explanation:

Average acceleration is the change in velocity over the change in time:

a = (v − v₀) / t

In the x direction:

aₓ = (6.11 cos (-54.2°) − 5.33 cos (37.9°)) / 2.00

aₓ = -0.316 m/s²

In the y direction:

aᵧ = (6.11 sin (-54.2°) − 5.33 sin (37.9°)) / 2.00

aᵧ = -4.11 m/s²

7 0
3 years ago
consider a charged parallel-plate capacitor. which combination of changes would quadruple its capacitance?
kogti [31]

Its capacitance Double the charge and double the plate area.

Doubling the distance between the plates of a capacitor double the capacitance. Doubling the distance between the plates of a capacitor quadruples the capacitance. As the distance between the plates decreases, the capacitance increases because the potential difference decreases.

Halving the distance between the plates of a parallel plate capacitor doubles the capacitance of the capacitor from its initial capacitance. When two or more capacitors are connected in parallel, the overall effect is that of a single equivalent capacitor with the sum of the plate areas of the individual capacitors. As we saw earlier all other factors being equal, more disk space equals more capacity.

Learn more about Capacitor here:-brainly.com/question/27393410

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4 0
2 years ago
Kilo-  -  1,000<br>deka-  -  10<br><br>How much larger is a kilo- than a deka-?
Ilya [14]
lets's \ take \ an \ example \ one \ gram: \\ \\ 0,001kg \\ \\ 0,01hg \\ \\ 0,1dag \\ \\ \boxed{1g} \\ \\ 10dg \\ \\ 100cg \\ \\ 1000mg  \\ \\ the \ units \ are \ rising \ and \ decreasing \ from \ 10 \ to \ 10 \ results \ \\ \\ a \ kilogram \ is \ 100 \ times \ larger \ than \ a \ dekagram
6 0
3 years ago
A brick is dropped (zero initial speed) from the roof of a building. The brick strikes the ground in 1.90 s. You may ignore air
Gekata [30.6K]

Answer: Height of building = 17.69m, velocity of brick = 18.6m/s

Explanation: From the question, the body has a zero initial speed, thus initial velocity (u) all through the motion is zero.

By ignoring air resistance makes it a free fall motion thus making it to accelerate constantly with a value of a = 9.8m/s^{2}.

Time taken to fall = 1.90s

a)

thus the height of the building is calculated using the formulae below

H = ut + \frac{1}{2} gt^{2}

but u = 0 , hence

H = \frac{1}{2} gt^{2}

H = \frac{1}{2} *9.8* 1.9^{2} \\\\H = 17.69m

b)

to get the value of velocity (v) as the brick hits the ground, we use the formulae below

v^{2} = u^{2} + 2aH

but u= 0, hence

v^{2} = 2gH\\

v^{2} = 2 * 9.8 * 17.69\\v = \sqrt{2 *9.8* 17.69} \\v = 18.62m/s

 

find the attachment in this answer for the accleration- time graph, velocity- time graph and distance time graph

8 0
4 years ago
What are the body measurements​
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Answer:

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3 years ago
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