Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
The property called cohesion
1. Treatable by a medical professional
2. Requires a medical diagnosis
<span>3. Lab tests or imaging always required
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Prokaryotic cells are simple, ancient cells without a nucleus. Eukaryotic cells are more complex and have a nucleus.
Answer:
there will have to be something to produce all the food so that other animals can eat
Explanation:
the consumers are important as when they eat they can have a high possibility to not starve to death as they have competition and can reproduce and then there is a possibility that that animal species may not become extinct
also when u eat u decompose so they are inportant as they decompose
as when they decompose they lay fertilisers for the soil in the floor so that other plants can grow amd flourish so the cycle can continue
