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Marat540 [252]
3 years ago
13

10. Which functional group is present in the molecule? Alcohol

Chemistry
1 answer:
mina [271]3 years ago
8 0

It carries at least one hydroxyl functional group ( i.e -OH ) bound to a saturated carbon atom.

Therefore the functional group present is -OH functional group.

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OH⁻
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Magnesium reacts with nitrogen to form magnesium nitride. The chemical formula for this reaction is Mg + N2 MgN2. What is the pr
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"Magnesium nitride" is the one product of the reaction among the choices given in the question that is correct. The correct option among all the options that are given in the question is the third option or option "C". I hope that this is the answer that has actually come to your great help.
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The solubility product of calcium fluoride (CaF2(s); fluorite) is 310-11 at 25C. Could a fluoride concentration of 1.0 mg L-1
Finger [1]

The given question is incomplete. The complete question is as follows.

The solubility product of calcium fluoride () is  at 25 degrees C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 200 mg/L of calcium?

Explanation:

Reaction equation for the given chemical reaction is as follows.

       CaF_{2} \rightleftharpoons Ca^{2+} + 2F^{-}

Therefore, expression for K_{sp} will be as follows.

        K_{sp} = [Ca^{2+}][F^{-}]^{2}

                     =

Also, moles of  per liter = \frac{\text{mass of F^{-} per L}}{\text{molar mass of F}}[/tex]

                = \frac{1.0 \times 10^{-3}}{19.0}

               = 5.263 \times 10^{-5} mol

Hence,    [F^{-}] = \frac{\text{moles of F^{-}}{volume}

                       = \frac{5.263 \times 10^{-5}}{1}

                      =  M

Now, moles of  per L = \frac{\text{mass of Ca^{2+} per L}}{\text{molar mass of Ca}}[/tex]

            = \frac{200 \times 10^{-3}}{40.1}

           =  M

Also,   [Ca^{2+}] = \frac{moles of Ca^{2+}}{volume}

                      = \frac{4.988 \times 10^{-3}}{1}

                     =  M

Hence, ionic product =

                 = (4.988 \times 10^{-3}) \times (5.263 \times 10^{-5})^{2}

                = 1.38 \times 10^{-11}

As, the ionic product is less than the K_{sp}, this means that the fluoride will be soluble in water containing the calcium.

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Equation: MgOH2 (s) --> MgO (s) + H2O (g)

And it's already balanced.

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Answer:

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