"Magnesium nitride" is the one product of the reaction among the choices given in the question that is correct. The correct option among all the options that are given in the question is the third option or option "C". I hope that this is the answer that has actually come to your great help.
The given question is incomplete. The complete question is as follows.
The solubility product of calcium fluoride () is at 25 degrees C. Will a fluoride concentration of 1.0 mg/L be soluble in a water containing 200 mg/L of calcium?
Explanation:
Reaction equation for the given chemical reaction is as follows.

Therefore, expression for
will be as follows.
=
Also, moles of per liter = \frac{\text{mass of F^{-} per L}}{\text{molar mass of F}}[/tex]
=
= 
Hence, ![[F^{-}] = \frac{\text{moles of F^{-}}{volume}](https://tex.z-dn.net/?f=%5BF%5E%7B-%7D%5D%20%3D%20%5Cfrac%7B%5Ctext%7Bmoles%20of%20F%5E%7B-%7D%7D%7Bvolume%7D)
=
= M
Now, moles of per L = \frac{\text{mass of Ca^{2+} per L}}{\text{molar mass of Ca}}[/tex]
=
= M
Also, ![[Ca^{2+}] = \frac{moles of Ca^{2+}}{volume}](https://tex.z-dn.net/?f=%5BCa%5E%7B2%2B%7D%5D%20%3D%20%5Cfrac%7Bmoles%20of%20Ca%5E%7B2%2B%7D%7D%7Bvolume%7D)
=
= M
Hence, ionic product =
=
= 
As, the ionic product is less than the
, this means that the fluoride will be soluble in water containing the calcium.
Equation: MgOH2 (s) --> MgO (s) + H2O (g)
And it's already balanced.
I had chemistry this semester too.