1, 2, 1, 2, in that order.
Answer:
See explanation
Explanation:
Carbon monoxide is toxic because it can successfully competes with oxygen for hemoglobin (Hb) sites according to the following equilibrium:
Hb(O₂)₄(aq) + 4CO(g) ⇄ Hb(CO)₄(aq) + 4O₂(g)
Based on LeChatelier’s Principle, CO poisoning can be reversed by applying O₂(g) to victim. This addition of O₂(g) increases system concentration of O₂(g) in the equilibrium reaction thereby overloading the product side of the equilibrium forcing it to shift to the left, decomposing the carboxyhemoglobin (Hb(CO)₄) and releasing the CO(g) and combining with O₂(g) to form more Hb(O₂)₄.
I believe it's ;
<span>one truck load is 2.5*1.5*1 = 3.75m^3 </span>
<span>7/3.75 = 1.86 loads, </span>
<span>so 2 trips must be made.
Hope this helped! :)</span>
Answer:
Cd(s) + AgNO₃(aq) → Cd(NO₃)₂ (aq) + Ag(s)
Oxidized: Cd
Reduced: Ag
Explanation:
Cd(s) + AgNO₃(aq) → Cd(NO₃)₂ (aq) + Ag(s)
Cd → Cd²⁺ + 2e⁻ Half reaction oxidation
1e⁻ + Ag⁺ → Ag Half reaction reduction
Ag changed oxidation number from +1 to 0
Cd changed oxidation number from 0 to +2
Let's ballance the electrons
( Cd → Cd²⁺ + 2e⁻ ) .1
( 1e⁻ + Ag⁺ → Ag ) .2
Cd + 2e⁻ + 2Ag⁺ → 2Ag + Cd²⁺ + 2e⁻
Finally the ballance equation is:
Cd(s) + 2AgNO₃(aq) → Cd(NO₃)₂ (aq) + 2Ag(s)
